<span>Put it in the form of y =mx +b, or in this instance, y> mx +b
move the (1/2) x to the right by adding it to both sides of the inequality
(1/3)y>(1/2)x +2
Multiply by 3 on both sides to get y by itself.
y>(3/2) x +6
This is a graph with y intercept of (0,6) and a moderate upward and to the right slope. Because it is > , the line on the graph will NOT be part of the solution.
The easiest way to find the side of the graph that the inequality satisfies is to use (0,0) and see if it works or doesn't work. In the original equation, 0-0>2 does NOT work, so the area where the inequality works is to the up and left of the graph, which should be a dotted line to show that the inequality is greater than only.
The point (6,-2) should work.
Test it. 6*(1/3)-(-2)*(1/2)>0 ; 2-(-1)=3, and 3>2 It does work.
The point (6,2) should not work
Test it. 6 *(1/3)-2(1/2)=2-1 ; 1 is NOT >2, so it does not work.
If the graph goes through the origin, then pick a point near the graph with a small x or y.</span>
Radical 63 can be broken down as radical 9 and 7. Radical 9 can be also 3 and you carry the radical 7. So radical 63 is basically 3 radical 7.
Answer:
Step-by-step explanation:
The happiest used in a test in statistics are the null and the alternative hypothesis. The null hypothesis is usually the default statement while the alternative hypothesis is thevopposite of the null hypothesis.
In this case study, the null hypothesis is u1 = u2: the average mean time it takes to accelerate to 30 miles per hour for car 1 is the same as that for car 2.
The alternative hypothesis is u1 > u2: the mean time it takes to accelerate to 30 miles per hour is greater than that for car 2 thus car 1 is slower to accelerate as it takes more time.
First, add all of the minutes together. You would get 75 minutes of practice per day.
Then you multiply 75 by 7, and you get 525 minutes.
He practices 525 minutes (or 8.75) hours per week
Answer:
16
Step-by-step explanation:
Using the rule of exponents/ radicals
= ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
, then
= ![\sqrt[3]{n^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%5E2%7D)
, then
= 8 ( cube both sides )
n² = 8³ ( take the square root of both sides )
n = 
= 
= 
= 
×
= 16
