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MariettaO [177]
4 years ago
15

A rectangular garden has a length of x + 2 ft. and a width of x + 8 ft. What must x be in order for the garden to have an area o

f 91 sq. ft.?
Mathematics
2 answers:
laila [671]4 years ago
8 0

Answer:

x=5

Step-by-step explanation:

5+2=7

5+8=13

13*7=91

Alex17521 [72]4 years ago
6 0

Answer: 5 ft

Step-by-step explanation:

Our equation can be (x + 8)(x + 2) = 91. Now we solve:

(x + 8)(x + 2) = 91

x^2 + 2x + 8x + 16 = 91    expand

x^2 + 10x + 16 = 91           simplify

x^2 + 10x - 75 = 0            subtract 91 from both sides

(x + 15)(x - 5) = 0               factor

x + 15 = 0              x - 5 = 0

x \neq \\ -15                    x = 5

x can't equal -15 because you cannot have negative feet, so x = 5 feet

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<u>SOLUTION: </u>

Given, A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China.  

We have to find the length and width of a similar rectangular screen  

We are also given that the length is 5 meters more than 3 times its width,  

Let width of rectangle be "b" meters, the its length will be 5 + 3b meters

And, the viewable area is 3,850 square meters.

\begin{array}{l}{\text { So, area }=3850} \\\\ {\text { Length } \times \text { width }=3850} \\\\ {(5+3 b) \times b=3850} \\\\ {5 b+3 b^{2}=3850} \\\\ {3 b^{2}+5 b-3850=0}\end{array}

Now,let us use quadratic formula:

\begin{array}{l}{\mathrm{x}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}} \\\\ {\text { Then, } \mathrm{b}=\frac{-5 \pm \sqrt{5^{2}-4 \times 3 \times(-3850)}}{2 \times 3}}\end{array}

\begin{array}{l}{\mathrm{b}=\frac{-5 \pm \sqrt{25+46200}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm \sqrt{46225}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm 215}{6}} \\\\ {\mathrm{b}=\frac{-5+215}{6} \text { or } \frac{-5-215}{6}} \\\\ {\mathrm{b}=\frac{210}{6} \mathrm{or} \frac{-220}{6}}\end{array}

Neglect negative values as width can’t be negative

b=\frac{210}{6}=35

so, width = 35 meters, then length = 5 + 3(35) = 5 + 105 = 110 meters

hence, the length and width of the similar rectangular screen are 110 meters and 35 meters respectively.

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