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3 years ago

Determine the first four terms of the sequence in which the nth term is...

Mathematics

2 answers:

Anon25 [30]3 years ago

7 0

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5

The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6

The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7

The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

Lelechka [254]3 years ago

3 0

Answer:

D. 1/5,1/6,1/7,1/8

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In a triangle, one angle is 3 times the first, another is 5 times the first. How large is the largest angle in degrees? round yo

Leno4ka [110]

let's recall that a triangle has a total of 180° for its interior angles.

x = first angle

3x = second angle, three times the first one

5x = third angle, five times the first one, and largest.

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2 years ago

Mr. Davis bought solar lights for a pathway at his house. The lights cost $29.95 each and have an

vlabodo [156]

He pays $223.65.

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X(29.95+2.00)

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3 years ago

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SVETLANKA909090 [29]

Answer:

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Step-by-step explanation:

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2 years ago

A dog sits at a corner of a square with side length 44 meters. the dog runs 10 meters along a diagonal toward the opposite corne

wlad13 [49]

Refer to the figure given below while reading the solution.

Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.

And then position B when traveled 5 m towards the right turning 90°.

We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).

Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).

Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.

The shortest distance of B from PQ = AC-AD
The shortest distance of B from SR = 44-(AC-AD)
The shortest distance of B from SP = AC+AD
The shortest distance of B from RQ = 44-(AC+AD)

So, the average of the shortest distances of B from each side is $\frac{(AC-AD)+44-(AC-AD)+(AC+AD)+44-(AC+AD)}{4}=\frac{44+44}{4}=22$

Hence, the average of the shortest distance of B from each side is 22 m

Learn more about average here-

brainly.com/question/24057012

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1 year ago

I saved the best for last :]

harkovskaia [24]

Answer:

a¹⁸b²⁴c⁵⁴

Step-by-step explanation:

(aᵇ)ᶜ = aᵇᶜ = aᵇ×ᶜ

(-aⁿ)ᵒᵈᵈ = -aⁿ

(-aⁿ)ᵉᵛᵉⁿ = aⁿ

aⁿ × aⁿ = aⁿ⁺ⁿ

_________

In this situation, 6 is an even exponent which means that the negative coefficient of this 9th degree monomial will be positive. Now the only step is to multiply the exponents by the exponent outside of the perenthesis which is 6.

so (-a³b⁴c⁹)⁶ = ((-a³)⁶(b⁴)⁶(c⁹)⁶) = ((a³ˣ⁶)(b⁴ˣ⁶)(c⁹ˣ⁶)) = ((a¹⁸)(b²⁴)(c⁵⁴)) = <em>a¹⁸b²⁴c⁵⁴</em>

4 0

2 years ago