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3 years ago

Factorize (2a-b)^2 -4(2a-b) -13

Mathematics

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

Hello!

`~~~~~~~~~~~~`

(2a-b)^2 -4(2a-b) -13 =

$v = 4a^{2} - 4ab + b^{2} - 8a +4b - 13$

~~~~~~~~~~~~`

Step-by-step explanation: All you have to do is Factor the polynomial.

Hope this helped you. Brainliest would be nice!

______________❤︎______________

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Answer:

$\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}$

Step-by-step explanation:

Step 1: Define significance level

In this hypothesis testing problem, significance levels α is selected: $0.05$ , the associated z-value from Laplace table:

Φ( $z$ ) = α - $0.5 = 0.05 - 0.5 = -0.45$

=> $z$ = $-1.645$

Step 2: Define null hypothesis ( $H_{0}$ ) and alternative hypothesis ( $H_{1}$ )

$H_{0}$ : rate of flu infection $p$ = 8.3% or 8.3/100 = 0.083

$H_{1}$ : rate of flu infection $p$ < 8.3% or 8.3/100 = 0.083

Step 3: Apply the formula to check test statistic:

$K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}$

with $f$ is actual sampling percent, $p$ is rate of flu infection of $H_{0}$ , $n$ is number of samples.

The null hypothesis will be rejected if $K < z$

Step 4: Calculate the value of K and compare with $z$

$K = \frac{(\frac{3.5}{100}) - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46$

We have $-2.46 < -1.645$

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As $H_{1}$ states)

Hope this helps!

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