The probability of getting first an odd number and second an even number IS 0.25
Step-by-step explanation:
Lets define the following events:
A: Probability of obtaining an odd number first time
B: Probability of obtaining an even number second time
and probability of ane events is defined as
P (Event) = number of ways event may happen / number of possible outcomes
Then:
P(A) = 3/ 6 =1/2
because we can have 1, 3,5 so event A occurs and there are six possible outcomes (1,2,3,4,5,6)
P(B) = 3/ 6 =1/2
because we can have 2, 4,6 so event b occurs and there are six possible outcomes (1,2,3,4,5,6)
the probaility that both events occur one after the other is
P(A and B) = P(A)*P(B) = 1/2* 1/2 = 1/4 = 0.25
This applies only if the chances that event B happening doesnt change after A happens. As A event is independent from B event, we can do this multiplication.
Solution: Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes
Someone is writing the answer so ill just give you this tip for whenever. A negitive times a negitive is positive a negative times a positive is negitive and a positive times a positive is positive (just had to add it to be complete)
