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gladu [14]
3 years ago
6

Which of the following lines is perpendicular to y=-2x+3?

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

The given line has equation:

y=-2x + 3

Compare to the general slope-intercept form: y=mx+c

This implies that m=-2 is the slope of the given line.

The slope of all lines perpendicular to the given line is the negative reciprocal of -2.

This implies that the slope of any line perpendicular to y=-2x+3 is

\frac{1}{2}

Now look through the options and choose the equation that is of the form:

y =  \frac{1}{2} x + \boxed { whatever\:  \: constant }

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seraphim [82]
The answer is 12 I promise
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3 years ago
WILL GIVE BRAINLIEST HELP. IMAGE THERE
Zinaida [17]

Answer:

First slope=0

second slope=0

Step-by-step explanation:

YW NOW BRAINLIEST PLEASE

5 0
3 years ago
Read 2 more answers
If you were to use the substitution method to solve the following system, choose the new
mestny [16]

Answer:

23x = -115

Step-by-step explanation:

In the substitution method, you must solve for 1 variable in 1 equation to replace it in the other equation. For the system:

2x - 7y = 4

3x + y = -17

Solving for y in the second equation:

y = -17 - 3x

Replacing y in the first equation:

2x - 7(-17 - 3x) = 4

2x + 119 + 21x = 4

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This is the new equation after use the substitution method.

5 0
3 years ago
Find f f'(x)=1+3sqrt(x) f(4)=25
wlad13 [49]
It appears that you have a derivative and want to integrate...

dy/dx=1+3√x 

y(x)=x+(2/3)x^(3/2)+C  you are given that f(4)=25 so we can solve for the constant of integration...

y(4)=25=4+16/3+C

21=16/3+C

(63-16)/3=C

47/3=C so

f(x)=x+(2/3)x^(3/2)+47/3

f(x)=(3x+2x^(3/2)+47)/3


6 0
3 years ago
2/(x^2)=4/x+1<br>can any one solve this for me please
levacccp [35]
2/X^2=4/X+1                                   times by both denominators
2(x+1)=4(x^2)
2x+2=4x^2
4x^2-2x-2=0
(2x+1)(2x-2)=0
x=2x+1 or 2x-2
x=-1/2 or 1
5 0
3 years ago
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