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Setler [38]
3 years ago
9

Simplify the expression: 2(4x-3)-7(x+1)

Mathematics
1 answer:
Aliun [14]3 years ago
4 0
2(4x-3)-7(x+1) first distribute
8x-6-7x+7 then combine the x's
<u>x+13 </u>
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3 years ago
Find the greatest common factor for 10,40
jonny [76]

The greatest common factor of 10 and 40 is 10.

5 0
3 years ago
Read 2 more answers
What is the next term in the geometric sequence?<br><br> 4/9,-4/3,4,...
Komok [63]

Answer:

-12

Step-by-step explanation:

r = -3

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7 0
2 years ago
What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

Diagonal 2(BD) = \sqrt{(2-2)^2+(3+5)^2} = 8 units

Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

                                                       = \frac{1}{2}\times 4\times 8

                                                       = 16 units²

Therefore, area of the given rhombus is 16 units².

5 0
3 years ago
Prove the quotient rule. hint: you can do this directly, but it may be easier to find the derivative of 1/x and then use the cha
Bess [88]
The quotient rule is
d(u/v) = (u dv - v du) / u2

d(u/v) can written as
d( u (1/v) )

Using the product rule and chain rule
d( u (1/v)) = u d(1/v) + (1/v) du
= u (-1/v2) dv + (!/v) du
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3 years ago
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