Answer:
There are 144 Php 5-coins, 72 Php 10-coins and 130 Php-1 coins
Step-by-step explanation:
The amount of the coins in the coin bank = Php 1,570
The number of Php 5-coins = 2 × The number of Php 10-coins
The number of Php 5 coins = The number of Php 1-coins + 14
Let 'x' represent the number of Php-5 coins, let 'y' represent the number of Php 10-coins, and let 'z' represent the number of Php 1-coins, we get;
x = 2 × y...(1)
x = z + 14...(2)
5·x + 10·y + z = 1,570...(3)
From equation (1) equation (2), and equation three, we have;
y = x/2
z = x - 14
5·x + 10·x/2 + x - 14 = 1,570
11·x - 14 = 1,570
x = (1,570 + 14)/11 = 144
The number of Php 5-coins, x = 144
y = x/2
∴ y = 144/2 = 72
The number of Php 10-coins, y = 72
z = x - 14
∴ z = 144 - 14 = 130
The number of Php 1-coins, z = 130
