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Keith_Richards [23]
3 years ago
13

AA3+2=AAA CC6+6=CBB (AB|C) ->S57->E73->S47->E57->S43->W26->S18->?

Mathematics
1 answer:
Paladinen [302]3 years ago
5 0
The question asks:
"Mark Atilius was expecting news from his friends with whom he agreed to reveal the great secret pyramids and spent his time at a nearby inn when he caught the attention of the Egyptian sitting beside him. He was even more surprised when he talked to him.
- You're Mark Atilius, are not you? she smiled - My name is Nefertari and I have a message for you from my grandmother. You should go right away if you want to get Pharaoh's belt you've been looking for all this time.
And he passed on the parchment he had just read.

<span> AA3 + 2 = AAA
CC6 + 6 = CBB
(AB | C) -> S57 -> E73-> S47-> E57-> S43-> W26-> S18->? </span>
Task: Find out the coordinates where Mark should come.<span> "

First, you need to solve for the position from which Mark starts. 
You know: 
</span><span>AA3 + 2 = AAA
Since 3 + 2 = 5,
553 + 2 = 555
Therefore A = 5.

Similarly: 
</span><span>CC6 + 6 = CBB 
Since 6+6 = 12, B = 2.
In order from the middle digit to be 2, the original one must have been 1.
Therefore B = 2 and C = 1

Hence, the starting position is: (AB, C) = (52, 1)

The following line gives you how many steps and in what direction Mark should go: S = south (negative vertical motion), N = north (positive vertical motion), E = east (positive horizontal motion), W = west (negative horizontal motion).

(52, 1) 
-> S57 -> (52, -56)</span> 
-> E73 -> (125, -56)
-> S47 -> (125, -103)
-> E57 -> (182, -103)
-> S43 -> (182, -146)
-> W26 -> (156, -146)
-> S18 -> (156, -164)

Hence, the coordinates that Mark should reach are (156, -164)
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NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
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Juan is making a model out of rhombi. Each rhombus will be connected to the one before it. Each rhombus will be 6 inches tall an
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He will need 12 sq. inches of Paper for each rhombus.

Given: 6 inches tall and 4 inches wide.

so, Length of the diagonals are 6 and 4 inches respectively.

Refer to figure.

The two diagonals cuts the rhombus into four equal parts, so

Area of one rhombus = 4 x (area of 1 part of the rhombus)

Now,

Area of 1 part of the rhombus = \frac{1}{2} x 3 x 2

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Area of one rhombus = 4 x 3 = 12 sq. inches

Hence, 12 sq. inches of Paper is needed for each rhombus.

Learn more about the "Finding the area of the rhombus" Here : brainly.com/question/10684261

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1 year ago
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Which pair of words describes this system of equations 3y=9x-6 2y+6x=4
pishuonlain [190]

Answer:

Consistent and dependent

Step-by-step explanation:

Given

3y = 9x - 6

2y + 6x = 4

Required

The words that describe the equations

Make y the subject in (2)

2y + 6x = 4

Collect like terms

2y = 4 - 6x

Divide through by 2

y = 2 - 3x

Substitute: y = 2 - 3x in (1)

3y = 9x - 6

3(2 - 3x) = 9x - 6

6 - 9x = 9x - 6

Collect like terms

9x+9x = 6+6

18x = 12

Solve for x

x = \frac{12}{18}

Simplify

x = \frac{2}{3}

Substitute x = \frac{2}{3} in y = 2 - 3x

y = 2 - 3*\frac{2}{3}

y = 2 - 2

y =0

So, we have:

x = \frac{2}{3} and y =0

<em>The system is consistent because it has at least 1 solution</em>

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6 0
3 years ago
) How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?
eimsori [14]

Question:

A solar power company is trying to correlate the total possible hours of daylight (simply the time from sunrise to sunset) on a given day to the production from solar panels on a residential unit. They created a scatter plot for one such unit over the span of five months. The scatter plot is shown below. The equation line of best fit for this bivariate data set was: y = 2.26x + 20.01

How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?

Answer:

51.65 kilowatt hours

Step-by-step explanation:

We are given the equation line of best fit for this data as:

y = 2.26x + 20.01

On a day that has 14 hours of possible daylight, the model prediction will be calculated as follow:

Let x = 14 in the equation.

Therefore,

y = 2.26x + 20.01

y = 2.26(14) + 20.01

y = 31.64 + 20.01

y = 51.65

On a day that has 14 hours of daylight, the model would predict 51.65 kilowatt hours

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