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STALIN [3.7K]
3 years ago
13

Multiply and simplify out theese brackets(X+1)(x+3)

Mathematics
1 answer:
Lorico [155]3 years ago
6 0
The method in which you do this problem would be to FOIL. First Outer Inner Last. You take the first terms and multiply them. x*x = x^2 (x to the second power). Then you do it with the rest of foil.
x*x = x^2
x*1 = x
x*3 = 3x
1*3 = 3
x^2 + x + 3x + 3 = X^2 + 4x + 3
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Find the sum of the first 48 terms of the following series, to the nearest integer.
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Answer:

3,672

Step-by-step explanation:

Given the sequence 6, 9, 12...

The sequence is an arithmetic sequence

first term a = 6

common difference d = 9 - 6 = 12 - 9 = 3

number of terms n = 48

Sn = n/2[2a+(n-1)d]

Substitute the given values

S48 = 48/2[2(6)+(48-1)(3)]

S48 = 24(12+(3*47))

S48 = 24(12+141)

S48 = 24(153)

S48 = 3,672

Hence the sum of the first 48terms is 3,672

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Lady_Fox [76]
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