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oksian1 [2.3K]
3 years ago
13

What is the value of n?

Mathematics
2 answers:
Ahat [919]3 years ago
8 0

Answer:

n=3

Step-by-step explanation:

if we raise both sides to the power n we get

54x^{7}y^{3}  = 3^{n}x^{2n}y^{n}*2x

so as you see y^{3} =y^{n} so n=3

musickatia [10]3 years ago
7 0

Answer:

abboga booga

Step-by-step explanation:

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Write three expressions that have the same value as 745 ÷ 30.
nataly862011 [7]

Answer:

(700+40+5)/30

10(745/3)

30x=745

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Suppose 300 nursing students took a certification test that is worth 100 points.
Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

Q_1 = 65

Median = 82

Q_3 = 88

Maximum = 100

Q_1 is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below Q_1 and about 75% lie above Q_1 .

Q_3 is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie belowQ_3 and about 25% lie above Q_3

i) .About how many students scored 65 or better?

Q_1 = 65

Since we know that 75% lie above Q_1 .

So, Number of students  scored 65 or better = 75\% \times 300 = \frac{75}{100} \times 300 =225

ii)About how many students scored 88 or better?

Q_3 = 88

Since we know that 25% lie above Q_3

So, Number of students scored 88 or better = 25\% \times 300 = \frac{25}{100} \times 300 =75

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0
3 years ago
On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes.
yanalaym [24]

Answer:

Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes

6 0
3 years ago
A quadratic equation is shown below:
AfilCa [17]

the solutions to a general quadratic equation is

X=-b±√b²-4ac/2a  ,, When ax²+bx+c=0

the discriminant is the expression under the radical b²−4ac

Part A:

discriminant is (-16)² - 4(9)(60) = -1904

there are two complex solutions  

Part B:  

4x² + 8x − 5 = 0

4x² + 10x -2x - 5=0

2x ( 2x + 5) - 1(2 x + 5) =0  

(2x + 5)(2x-1) = 0

      /                     \

    /                          \

2x+5 = 0                 2x-1 =0    

x = -5/2                     x = 1/2

5 0
3 years ago
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