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3 years ago

Can you please simplify (x^2)^5 ?

Mathematics

1 answer:

Sloan [31]3 years ago

8 0

(x^2)^5 = x^(2*5) = x^10

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For the diagram shown, x = 80 and y = 30. Determine the value of z. A) 20 B) 40 C) 50 D) 100

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Answer:D

Step-by-step explanation:

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3 years ago

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Help pls what is 2*123/56+7=

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Answer:

Multiply 123 times 2 (246) and then divide that by 56 and add 7 to get your final answer.

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3 years ago

Simplify the following expression

exis [7]

Answer:

See below

Step-by-step explanation:

√160c⁵d⁴

= √160 * √c⁵ * √d⁴

= √16 * √10 * √c² * √c² * √c * √d² * √d²

= 4 * √10 * c * c * √c * d * d

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4 years ago

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What is the measure of an interior angle of a regular 10-gon?

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Answer: In geometry, a decagon (from the Greek δέκα déka and γωνία gonía, "ten angles") is a ten-sided polygon or 10-gon. The total sum of the interior angles of a simple decagon is 1440°.

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3 years ago

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A bottle contains 255 coins. 1/3 of the coins are ?1.00. 110 of the coins are 50p coins. the rest are 20p coins. work out the to

aliina [53]

Answer:

£152.

Step-by-step explanation:

We have been given that a bottle contains 255 coins. 1/3 of the coins are £1.00.

Let us find 1/3 of 255 to find the number of £1 coins.

$\£1\text{ coins}=\frac{1}{3}\times 255$

$\£1\text{ coins}=85$

This means we have £85.

We are also told that 110 of the coins are 50 p coins.

$\text{Value of 50 p coins}=\£0.50\times 110$

$\text{Value of 50 p coins}=\£55$

Let us figure out number of 20 p coins by subtracting the number of £1 coins and 50 p coins from 255.

$\text{Number of 20 p coins}=255-(85+110)$

$\text{Number of 20 p coins}=255-(195)$

$\text{Number of 20 p coins}=60$

$\text{Value of 20 p coins}=\£0.20\times 60$

$\text{Value of 20 p coins}=\£12$

Now let us find total value of the coins contained in the bottle by adding the values of £1 coins, 50 p coins and 20 p coins.

$\text{The total value of the coins}=\£85+\£55+\£12$

$\text{The total value of the coins}=\£152$

Therefore, the total value of the coins contained in the bottle is £152.

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3 years ago

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