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3 years ago

Simplify the expression 5/x^-2y^5

Mathematics

1 answer:

DENIUS [597]3 years ago

5 0

Answer:

$\Lagre\Huge\boxed{\dfrac{5}{x^{-2}y^5}=\dfrac{5x^2}{y^5}}$

Step-by-step explanation:

$a^{-n}=\dfrac{1}{a^n}\to x^{-2}=\dfrac{1}{x^2}\\\\\text{therefore}\\\\\dfrac{5}{x^{-2}y^5}=\dfrac{5}{\frac{1}{x^2}\cdot y^5}=\dfrac{5}{y^5}\cdot\dfrac{x^2}{1}=\dfrac{5x^2}{y^5}$

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CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

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