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klio [65]
3 years ago
11

Simplify the expression 5/x^-2y^5

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

\Lagre\Huge\boxed{\dfrac{5}{x^{-2}y^5}=\dfrac{5x^2}{y^5}}

Step-by-step explanation:

a^{-n}=\dfrac{1}{a^n}\to x^{-2}=\dfrac{1}{x^2}\\\\\text{therefore}\\\\\dfrac{5}{x^{-2}y^5}=\dfrac{5}{\frac{1}{x^2}\cdot y^5}=\dfrac{5}{y^5}\cdot\dfrac{x^2}{1}=\dfrac{5x^2}{y^5}

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