The correct answer is 0.44ml
For information, promethazine is a neuroleptic antihistamine inhibitor of H1 receptors of the phenothiazine family. It is a medicine used in the treatment of allergy (like rhinitis) and transient insomnia.
To respond to this exercise, it is necessary to cross-multiply.
In the antihistamine bottle solution:
25 mg corresponds to 1 ml
11 mg corresponds to: 11/25 = 0.44 ml of the solution.
This 0.44ml is taken from the bottle and put to the syringe.
Answer: K+ and P 3−
Explanation:
Electrostatic force of attraction is the attraction between different molecules that comes from them being electrically charged.
For molecules to have an electrostatic force of attraction, they need to have opposing charges because like charges repel each other but opposite charges attract.
In the question above, the only option that has opposing charges is option D so this is the correct option.
The answer is B. Chemical change
The real situation with this is that if since both proteins and DNA contain carbon and oxygen, both molecules in the phage progeny would have received the radioactive isotopes. Hershey and Chase would have been unable to isolate only DNA molecules or proteins that contain the radioactive isotopes of these elements.
Hydrogen gas and oxygen gas react to form liquid water according to the following equation:
2H₂ + O₂ → 2H₂O
a. Converting our given masses of each gas to moles, we have:
(25 g H2)/(2 × 1.008 g/mol) = 12.4 mol H2; and
(25 g O2)/(2 × 15.999 g/mol) = 0.781 mol O2.
From the equation, two moles of H2 react with every one mole of O2. To fully react with 12.4 moles of H2, as we have here, one would need 6.2 moles of O2, which is far more than what we're actually given. Thus, the oxygen is our limiting reactant, and as such it will be the first reactant to run out.
b. Since O2 is our limiting reactant, we use it for determining how much product, in this case, H2O, is produced. From the equation, there is a 1:1 molar ratio between O2 and H2O. Thus, the number of moles of H2O produced will be the same as the number of moles of O2 that react: 0.781 moles of H2O. The mass of water produced would be (0.781 mol H2O)(18.015 g/mol) ≈ 14 grams of water (the answer is given to two significant figures).
c. Since the hydrogen reacts with the oxygen in a 2:1 ratio, twice the number of moles of oxygen in hydrogen is consumed: 0.781 mol O2 × 2 = 1.562 mol H2. Since we began with 12.4 moles of H2, the remaining amount of excess H2 would be 12.4 - 1.562 = 10.838 mol H2. The mass of the excess hydrogen reactant would thus be (10.838 mol H2)(2 × 1.008 g/mol) ≈ 22 grams of hydrogen gas (the answer is given to two significant figures).
