The Percent composition of MgO is 60.304 % and 39.696 % respectively.
<h3>
What percentage of the given chemical is there?</h3>
Mg + 1/2O₂ -------> MgO
We now want to know the percent composition of MgO in light of this reaction. Since the original reactants' and the product's mass are not provided, we can use the component's atomic weights to solve this problem.
Let's compute the molar mass of MgO since Mg has a molecular weight of 24.305 g/mol and O has a molecular weight of 15.999 g/mol:
molar mass of 
Now with this weight, let's see the percent composition of this compound:
Mg percentage =
%
O percentage = 
%
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
Learn more about percent composition here:-
brainly.com/question/11885179
#SPJ4
<u>Answer:</u> The correct option is enough solvent to make 1.00 L of solution
<u>Explanation:</u>
A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.......(1)
We are given:
Molarity of solution = 0.500 M
Moles of solute = 0.500 moles
Putting values in equation 1, we get:
Hence, the correct option is enough solvent to make 1.00 L of solution
<span>3Ca + 2AlPO4 -> 2Al + Ca3(PO4)2 . . .the coefficient for Ca is 3.</span>
The balls are not perfectly elastic, but the main reason is probably air.
Explanation:
When 2 adjacent balls have any distance between them, there is air in the space. When the moving neighbor comes at a stationary ball the moving ball has to push the air out of the way.
I hope this helps
Answer:
9.93
Explanation:
Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.
pH + pOH = pKw
3.30 + pOH = -log(5.84 × 10^-14) = 13.23
pOH = 13.23 - 3.30 = 9.93
The pOH of the solution is 9.93.
