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Mashcka [7]
3 years ago
11

23. What are the correct formulas and coefficients for the products of the following double replacement reaction? Al(OH)3 + H3PO

4 → *
a. AlPO4 + H2O

b. AlPO4 + 3 H2O

c. H3Al + (OH)3PO4

d. 3AlPO4 + H3(OH)3

24. What type of reaction is 2S(s) + 3O2 (g) → 2SO3(g)? *

a. combination reaction

b. decomposition reaction

c. single replacement reaction

d. double replacement reaction
Chemistry
1 answer:
NikAS [45]3 years ago
3 0
23. The correct answer would be a (AlPO4 + H2O).

This is an example of a neutralization reaction (an acid and a base react to form water and a salt).

24. a, combination reaction. There are two reactants and one product.
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Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
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The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

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Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

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x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

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