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Mashcka [7]
3 years ago
11

23. What are the correct formulas and coefficients for the products of the following double replacement reaction? Al(OH)3 + H3PO

4 → *
a. AlPO4 + H2O

b. AlPO4 + 3 H2O

c. H3Al + (OH)3PO4

d. 3AlPO4 + H3(OH)3

24. What type of reaction is 2S(s) + 3O2 (g) → 2SO3(g)? *

a. combination reaction

b. decomposition reaction

c. single replacement reaction

d. double replacement reaction
Chemistry
1 answer:
NikAS [45]3 years ago
3 0
23. The correct answer would be a (AlPO4 + H2O).

This is an example of a neutralization reaction (an acid and a base react to form water and a salt).

24. a, combination reaction. There are two reactants and one product.
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Please fill this formula​
Maurinko [17]
1.) Na
2.) Cl ( at the second blank)
sodium metal+hydrochloric acid
3 0
2 years ago
A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem
ira [324]

This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

Q=mC(T_f-T_i)\\

Which has to be solved for the final temperature, T_f as follows:

T_f=T_i+\frac{Q}{mC}

Finally, we plug in the numbers to obtain:

T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C

However, this result is not given in the choices.

Learn more:

  • brainly.com/question/14383794
8 0
2 years ago
A sample of gas X occupies 10 mº at a pressure of 120 kPa.
Mashutka [201]

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = 10\textrm{ m}^{3}

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = 3\textrm{ m}^{3}

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}

New pressure of gas = 400 KPa

5 0
2 years ago
If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

7 0
3 years ago
What kind of simple machine is a shovel
Minchanka [31]
I think a shovel is a wedge simple machine.
8 0
2 years ago
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