Answer:
Easiest and fastest way is to graph both equations into a graphing calc and trace the graph to where they intersect.
Alternatively, you can use substitution to solve for your answer.
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Assuming the fractions are being multiplied
Factorise the denominators of both fractions
x² - 3x - 10 = (x - 5)(x + 2)
x² + x - 12 = (x + 4)(x - 3)
The product can now be expressed as
× 
Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving
= 
Answer:
9-x
Step-by-step explanation:
Answer:
0.90
Step-by-step explanation:
hope this helps
Answer:
option B
Given : |x + 4| < 5
A. –5 > x + 4 < 5
B. –5 < x + 4 < 5
C. x + 4 < 5 and x + 4 < –5
D. x + 4 < 5 or x + 4 < –5
In general , |x|< n where n is positive
Then we translate to -n < x < n
|x + 4| < 5
5 is positive, so we translate the given absolute inequality to
-5 < x+4 < 5
So option B is correct