Question

3 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Answer 1

Answer:

Option C

Step-by-step explanation:

The sum of finite geometric sequence states the following:

$s_{n} =$Σ$a_{i} r^{i-1} = a_{1}(\frac{1-r^{n} }{1-r} )$

In this case, $r = \frac{900}{1500} = \frac{9}{15} = \frac{3}{5}$, and $i = 10$

Therefore,

$1500( 1 + \frac{3}{5} + (\frac{3}{5})^{3} + (\frac{3}{5})^{4} + (\frac{3}{5})^{5} + (\frac{3}{5})^{6} + (\frac{3}{5})^{7} + (\frac{3}{5})^{8} + (\frac{3}{5})^{9}) = 1500( 2,4848) = 3.727, 3251$ ≈  $3.727$

Therefore, the correct answer is the option C