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Luden [163]
3 years ago
7

3 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

Option C

Step-by-step explanation:

The sum of finite geometric sequence states the following:

s_{n} =Σa_{i} r^{i-1} = a_{1}(\frac{1-r^{n} }{1-r} )

In this case, r = \frac{900}{1500} = \frac{9}{15} = \frac{3}{5}, and i = 10

Therefore,

1500( 1 + \frac{3}{5} + (\frac{3}{5})^{3} + (\frac{3}{5})^{4} + (\frac{3}{5})^{5} + (\frac{3}{5})^{6} + (\frac{3}{5})^{7} + (\frac{3}{5})^{8} + (\frac{3}{5})^{9}) = 1500( 2,4848) = 3.727, 3251 ≈  3.727

Therefore, the correct answer is the option C

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Find the sum of the following infinite sequence: 8, 2, .5, …
lubasha [3.4K]
Answer:
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8 , 2 , 0.5 , ...... etc

The general formula of the geometric sequence is:
a1 , a1*r , a1*r² , ......

Comparing the general form with the given, we would find that:
a1 = 8
a1 * r = 2
Therefore:
8*r = 2
r = 2/8 = 0.25

We can double check using another term as follows:
a1 = 8
a1*r² = 0.5
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Now, we will get the sum of the sequence as follows:
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Hope this helps :)
3 0
3 years ago
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