Answer:
Step-by-step explanation:
The question is incomplete since they do not give information about the Car type 3.
We will do it in a generic way, we will say that the Car type 3 has a mean of M and a standard deviation SD.
We would be:
P (CT3 <550) = P [z <(550 - X) / SD]
Now if we give it values, for example that X = 600 and SD = 120
It would remain:
P (CT3 <550) = P [z <(550 - 600) / 120]
P (CT3 <550) = P [z <-0.42]
We look for this value in the normal distribution table (attached) and it shows us that the probability is approximately 0.3372, that is, 33.72%
What you need to do is replace the X and SD values of theCar type 3 in the equation above how I just did and you will get the result.
