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2 years ago

15 points!!! GEOMETRY help please!! Questions attached!

Mathematics

1 answer:

Alborosie2 years ago

3 0

7.
$\text{If the line segment labeled 6 is tangent to the circle then is rectangle triangle.}\\\\\text{ We can use Pythagorean theorem.}$

$x^2=2.5^2+6^2\\x^2=6.25+36\\x^2=42.25\\x=\sqrt{42.25}\\x=6.5\\\\Answer:\boxed{6.5}$

8.
$\text{If BC is tangent to circle then m}\angle OBC=90^o$

$\text{We can use the converse of Pythagorean theorem}$

$8\ and\ 12\\\\8^2+12^2=20^2\\64+144=400\\208=400\ -FALSE\\\\8;\ 4\sqrt{21}\\\\8^2+(4\sqrt{21})^2=20^2\\64+16\cdot21=400\\64+336=400\\400=400\ -O.K.\\\\12\ and\ 14\\\\12^2+14^2=20^2\\144+196=400\\340=400\ -FALSE\\\\10\ and\ 10\sqrt3\\\\10^2+(10\sqrt3)^2=20^2\\100+100\cdot3=400\100+300=400\\400=400\ -O.K.\\\\14\ and\ 4\sqrt{51};\ 4\sqrt{51} > 20 - FALSE$
$\text{because the line segment labeled 20 is the longest side of the triangle}$
<span>

$Answer:\ \boxed{8\ and\ 4\sqrt{21};\ 10\ and\ 10\sqrt3}$
</span>

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