Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?
1 answer:
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The answer is a = 3/4 = 0.75
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
![\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%20%7Ba%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B81%7D%20%20%20%5C%5C%20%204a%20%3D%203)
Divide both sides by 4:
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
Divide both sides by 4: