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const2013 [10]
3 years ago
14

Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?

Mathematics
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

He showed that f(n) ÷ f(n - 1) was a constant ratio.

Given that Jake has proved that a function f(x) is a geometric sequence.

GEOMETRIC SEQUENCE:  A geometric sequence is a sequence of numbers where each term is found by multiplying the preceding term by a constant called the common ratio, r.

So, in Jame's proof, he showed that each term is multiplied by a constant to get the next term.

That is, if 'c' is the constant that was used in the proof, then we must have

This implies that

Therefore, he showed that  f(n) ÷ f(n - 1) was a constant ratio.

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5) Lee's model airplane flies at 18 miles per hour. Lee took the plane to a field in windy weather. It took six minutes to fly 2
kap26 [50]

The wind is blowing at the rate of 4 miles per hour

<h3>Speed and distances</h3>

The formula for calculating speed is expressed as:

Speed = Distance/Time

Given the following parameters

Speed of airplane = 18 miles per hour

Speed in wind = 2.2 * 10  = 22 miles/hr

Speed of the wind = 22 - 18

Speed of the wind = 4mi/hr

Hence the wind is blowing at the rate of 4 miles per hour

Learn more on speed here: brainly.com/question/4931057

7 0
2 years ago
2/9 converted into decimal rounded to the nearest hundreth​
balandron [24]

Answer:

0.22

Step-by-step explanation:

2/9 as a decimal is 0.22222222

This number rounded off to its nearest hundredth is 0.22

Hope it helped

8 0
3 years ago
Read 2 more answers
If x = 2 and y = -3, then what is -xy2
Sophie [7]

Answer:

-18

Step-by-step explanation:

Step 1: Substitute your x and y values in

-(2)(-3)^{2} \\(-2)9\\-18

Therefore the answer when x = 2 and y = 3 is -18

3 0
3 years ago
Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0
artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2  + \frac{d^2f(0,0)}{dydx} x*y

So let's find all the terms:

Remember that:

\frac{dsin(ax)}{dx}  = a*cos(ax)

\frac{dcos(ax)}{dx} = -a*cos(ax)

f(0,0) = sin(0*0) = 1.

\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y

\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y

\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 =  -\frac{1}{2}  *y^2*sin(0*0)*x^2 = 0

\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 =  -\frac{1}{2}  *x^2*sin(0*0)*y^2 = 0

\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0
3 years ago
Please help!
aivan3 [116]

Answer:                                                                                                                    695.52 cm3 Try using calculatorsoup dot com Significant Figures auto?                                                                                                                                

Step-by-step explanation:

3 0
3 years ago
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