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Bas_tet [7]
3 years ago
8

Assume the following variable definition appears in a program:

Computers and Technology
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

cout << setprecision(2)<< fixed << number;

Explanation:

The above statement returns 12.35 as output

Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.

The statement starts by setting precision to 2 using setprecision(2)

This is immediately followed by the fixed manipulator;

The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;

Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.

The fixed manipulator is then followed by the variable to be printed.

See code snippet below

<em>#include <iostream>  </em>

<em>#include <iomanip> </em>

<em>using namespace std;  </em>

<em>int main()  </em>

<em>{  </em>

<em> // Initializing the double value</em>

<em> double number = 12.3456;  </em>

<em> //Print  result</em>

<em> cout << setprecision(2)<< fixed << number;  </em>

<em> return 0;  </em>

<em>}  </em>

<em />

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