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Harman [31]
2 years ago
12

Can the product of a whole number and a decimal number less than 1 ever be greater than a whole number

Mathematics
1 answer:
creativ13 [48]2 years ago
7 0
No. The product of a whole number and a decimal number less than 1 will be greater than the whole number multiplied into. For this theorem to be proven. Let us state the mathematical expression into numbers such that <span><span>
1. </span><span> N x 0.1 = N/0.1 < N</span></span> <span><span>
2. </span> 1 x 0.5 = 0.5 </span> <span><span>
3. </span><span> 2 x 0.1 = 0.2</span></span> <span><span>
4. </span><span> 100 x 0.55 = 55</span></span> 

These three examples and stances then suggest the claim that the product is not equal to the whole number used in the equation.



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Can I please have help with question 2) a and b
Ulleksa [173]

Answer:

\frac{10\sqrt{6} }{3} and \frac{11\sqrt{3} }{3}

Step-by-step explanation:

(a)

A = \frac{1}{2} × 4\sqrt{2} × \frac{5}{\sqrt{3} }

   = 2\sqrt{2} × \frac{5}{\sqrt{3} }

   = \frac{10\sqrt{2} }{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

= \frac{10\sqrt{6} }{3} units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4\sqrt{2} )² + (\frac{5}{\sqrt{3} } )²

    = 32 + \frac{25}{3}

    = \frac{96}{3} + \frac{25}{3}

    = \frac{121}{3} ( take the square root of both sides )

h = \sqrt{\frac{121}{3} } = \frac{11}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

h = \frac{11\sqrt{3} }{3}

 

7 0
3 years ago
The table shows the outputs y for different inputs x:
Rasek [7]
Part A: Yes, the data represent a function. The definition of a function is a relation in which no value of x will have two different values of y.
(Every time you plug in 3 as x, you will always get 4 as y; it's ok if you plug in 3 and 5 as x and get the same y, you just can't get two different y's for one x; sorry, it is pretty confusing). None of the numbers in the table repeat, so we can safely say that the relation is a function.

Part B: All we have to do is plug in 11 for x in the function given to find the answer:
f(x)=5x-21\\f(x)=5(11)-21\\f(x)=55-21\\f(x)=34
In the table, y = 8 when x = 11, but in the function given, y = 34 when x = 11, so the function given is greater.

Part C: To find the answer to C, just plug in 99 for f(x), as it tells you to do:
f(x) = 5x-21\\99=5x-21\\99+21=5x-21+21\\120=5x\\120/5=5x/5\\24=x
5 0
3 years ago
Read 2 more answers
A vehicle uses 1 gallons of gasoline to travel 13 miles. At this rate, how many mile
Brrunno [24]
1 gallon (it’s stayed in the question)
6 0
3 years ago
This is due Monday but I want to get it done today, because the teacher is still going to check it, and I have practicly nothing
Crank
You don’t have anything attached:(
7 0
3 years ago
The average of 4, 9, 16, 25 and x is 2x. What is the value of x? A) 4 B)6 A)9 C)9 D)12
Elodia [21]
The average of 4, 9, 16, 25 and x is 2x means that;
(4+9+16+25+x)/5=2x
Multiply both side by 5
5(54+x)/5=2x(5)
54+x=10x
Subtract x to both side
54+x-x=10x-x
54=9x
Divided 9 to both side
54/9=9x/9
x=6
Check:
Substitute x with 6
(4+9+16+25+x)/5=2x
(4+9+16+25+6)/5=2(6)
60/5=12
12=12; so x=6 which marks B as the correct answer. Have a nice day!
5 0
2 years ago
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