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Scorpion4ik [409]
3 years ago
14

Find the difference

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
It’s pretty simple just subtract
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Find the area of the surface. the part of the hyperbolic paraboloid z = y2 − x2 that lies between the cylinders x2 + y2 = 16 and
meriva
Parameterize the surface (call it \mathcal S) by

\mathbf s(u,v)=\langle u\cos v,u\sin v,u^2\sin^2v-u^2\cos^2v\rangle=\langle u\cos v,u\sin v,-u^2\cos2v\rangle

with 4\le u\le5 and 0\le v\le2\pi, which yields

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv

Then the area of \mathcal S is given by the surface integral

\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=4}^{u=5}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv=\dfrac{(101^{3/2}-65^{3/2})\pi}6
8 0
3 years ago
If equation of a circle is x^2 + y^2 + 6x + 4y + 10 = 1 What is this equation written in its standard form?
Darya [45]

\text{The equation of a circle in standard form:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h,\ k)-center\\r-radius\\---------------------------\\\\Use\ (a+b)^2=a^2+2ab+b^2\\\\---------------------------

x^2+y^2+6x+4y+10=0\qquad\text{subtract 10 from both sides}\\\\x^2+6x+y^2+4y=-10\\\\x^2+2x\cdot3+y^2+2y\cdot2=-10\qquad\text{add}\ 3^2\ \text{and}\ 2^2\ \text{to both sides}\\\\(x^2+2x\cdot3+3^2)+(y^2+2y\cdot2+2^2)=-10+3^2+2^2\\\\(x+3)^2+(y+2)^2=-10+9+4\\\\\boxed{(x+3)^2+(y+2)^2=3}

5 0
3 years ago
Pls helppp I need it in less than 7 min
gladu [14]

Hello from MrBillDoesMath!

Answer:     21 ^ (1/3)

Discussion:


The cube root of a  number is the same as raising the number of the third power.

Thank you,

MrB

7 0
4 years ago
What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?
11111nata11111 [884]

Answer:

R' = (-1,-0.5)

Step-by-step explanation:

See attachment for complete question.

From the attachment:

P = (-3,-3)

R = (1,2)

Dilation:

D_{(0.5,P)}

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

R = (1-(-3),2-(-3))

R = (1+3,2+3)

R = (4,5)

Next, apply dilation factor 0.5

R' = R * 0.5

R' = (4,5) * 0.5

R' = (4* 0.5,5* 0.5)

R' = (2,2.5)

Lastly, measure R' from the origin by adding the coordinates of P to R'

R' = (2+(-3),2.5+(-3))

R' = (2-3,2.5-3)

R' = (-1,-0.5)

6 0
3 years ago
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