Find the difference

This question is for ktishler1 what is 1+1?

WARRIOR [948]

Answer: 11

if u put 1 and 1 together

u get 11

8 0

3 years ago

Read 2 more answers

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

What is the equation of a circle with center at (0, -5) and radius of 7.

timurjin [86]

Answer:

x²+(y-5)²=49

Step-by-step explanation:

3 0

3 years ago

WILL GIVE BRAINLIEST FOR RIGHT ANSWER

Snowcat [4.5K]

Answer:

1.5

Step-by-step explanation:

2 ft. / the number of sides for width (2) = 1 then 3 ft. / number of sides for length (2) = 1.5

1.5 x 1 = 1.5

4 0

3 years ago

Estimate the solution to the system of equations. 7x−y=7 x+2y=6

ElenaW [278]

Answer:

I am not sure how your teacher wanted you to estimate the answer but I solved it for you. Hopefully this helps.

Step-by-step explanation:

7x-y=7

x+2y=6

14x-2y=14

x+2y=6

add both equations

15x=20

x=20/15

x=4/3

x+2y=6

4/3+2y=6

2y=6-4/3

2y=18/3 -4/3

2y=14/3

divide both sides by 2

y= 14/3 divided by 2

y=14/3(1/2)

y=14/6

2y=

3 0

3 years ago