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sveticcg [70]
3 years ago
5

740% as a mixed number

Mathematics
1 answer:
alex41 [277]3 years ago
5 0
740% as a fraction is 37/5.
37/5 as a mixed number is 7 2/5.

Hope this helps! Good luck.
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Help I need this today
Nadusha1986 [10]

Answer:

x=70

y=75

Step-by-step explanation:

2x+x+5-35=180

3x-30=180

3x=210

x=70

2(70)-35=105

180-105=75

y=75

3 0
3 years ago
Help show works rep by step I’ll give brainly
masha68 [24]

Answer:

4 lbs left after 5 days

Step-by-step explanation:

First, you need to step up an equation!

You know that Soomin has a total of 20 pounds and that she's using it, so you are going to use subtraction.

She uses 3 1/5 pounds per day so you write:

20 - 3 1/5x

and you know that she wants to know how much she has left after 5 days so you replace the x with 5:

20 - (3 1/5) * 5

Multiply first:

20 - 16

After Subtracting you get the answer:

4 lbs left

8 0
2 years ago
Read 2 more answers
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
A store in Campbell purchased a crystal sculpture at a cost of $100 and marked it up 100%. Later on, Stefan bought the crystal s
gtnhenbr [62]

Answer:

$218

Step-by-step explanation:

$100 times 100% = $200

9% of 200 = 200X.09 = 18

200 + 18 = 218

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Re download it or sum
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