Numbers are n, n+2 and we have n(n+2)=7224. Or
n^2+2n-7224=0
Using the quadratic equation
n=84. So n+2=86
The numbers are 84, 86
Answer:
165
Step-by-step explanation:
180-15=165
<u>Answer:</u>
Equation t = 5c + 6d represents total cost t of c large pizzas and d large one-topping pizzas
<u>Solution:</u>
Given that
Cost of large pizza = $5 each
Cost of large one-topping pizza = $6 each
Need to write the equation that represents total cost t of c large pizzas and d large one topping pizzas.
From given information
Cost of 1 large pizza = 5
So cost of c large pizzas = c x 5 = 5c
Cost of 1 large one-topping pizza = 6
So cost of d large one-topping pizzas =d x 6 = 6d
<em>Total cost t = cost of c large pizzas + cost of d large one-topping pizzas </em>
=> t = 5c + 6d
Hence equation t = 5c + 6d represents total cost t of c large pizzas and d large one-topping pizzas.
Answer:
see explanation
Step-by-step explanation:
Given
2BD = 7BT , then
2(d - b ) = 7(t - b) ← distribute both sides
2d - 2b = 7t - 7b ( add 7b to both sides )
2d + 5b = 7t, thus
2![\left[\begin{array}{ccc}10.5\\10\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10.5%5C%5C10%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 5![\left[\begin{array}{ccc}0\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= 7t
![\left[\begin{array}{ccc}21\\20\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}0\\15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= 7t
![\left[\begin{array}{ccc}21\\35\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C35%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= 7t , thus
t = 
= ![\left[\begin{array}{ccc}3\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Hence T = (3, 5 )
