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2 years ago

15

Simplify 45a²b __________ 30AB

1 answer:

kogti [31]2 years ago

8 0

Answer:

15ab

Step-by-step explanation:

if the AB is capital on purpose then its 15a^2b over AB

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What is the solution to this inequality?<br> -4X > 500

Tcecarenko [31]

Answer: x < -125

Step-by-step explanation:

-4x / (-4) < 500 / (-4)

x < -125

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3 years ago

What are the coordinates of A?

Nitella [24]

Answer:

The coordinates of A could be anything in the form of (x, y, z) if you have a third axis. First you count where A is on the x-axis then the y-axis and if you have a 3-dimensional graph then the z-axis.

Step-by-step explanation:

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3 years ago

Three of the angles of a polygon are

zmey [24]

Answer:

three angles of a polygon are each 105.5,the sum of the angles in the polygon is 2520. find each of the other angles if they are equal to each other. For a polygon with n sides and n angles, the sum of the measures of all the interior angles equals (n-2)180 degrees. 16-3=13

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2 years ago

X+3/2 + (x-1) = 4/5

tester [92]

Answer:

x = $\frac{3}{20}$

Step-by-step explanation:

Given

x + $\frac{3}{2}$ + (x - 1) = $\frac{4}{5}$

Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10x + 15 + 10(x - 1) = 8

10x + 15 + 10x - 10 = 8

20x + 5 = 8 ( subtract 5 from both sides )

20x = 3 ( divide both sides by 20 )

x = $\frac{3}{20}$

3 0

2 years ago

Read 2 more answers

A shipping container shaped like a rectangular prism must have a maximum volume of 10 cubic yards. If the container is 2 1/2 yar

denpristay [2]

Answer:

$1\frac{1}{7} yards$

Step-by-step explanation:

The maximum volume the shipping container can have is 10 cubic yards.

The volume of a rectangular prism is given as:

V = L * W * H

where L is length, W is width and H is height.

To find the maximum height of the container, make H the subject of formula:

$H = \frac{V}{L * W}$

We have been given the length and width of the container as 2 1/2 yards and 3 1/2 yards respectively.

Hence, the maximum height is:

$H = \frac{10}{2\frac{1}{2} * 3\frac{1}{2} } \\\\H = \frac{10}{\frac{5}{2} * \frac{7}{2} }$

$H = \frac{10}{\frac{35}{4} } \\\\H = \frac{10 * 4}{35} \\\\H = \frac{40}{35} = \frac{8}{7} = 1\frac{1}{7}$

The maximum height of the container is $1\frac{1}{7} yards$ .

7 0

3 years ago