Kent is twirling a ball attached to a string in a clockwise direction. If Kent lets go of the string, which of the following des
cribes the motion that the ball will take if there are no gravitational forces influencing the motion of the ball?
2 answers:
Kent's ball will go in the direction that the ball is going right when he lets go of it.
Imagine this like an analog clock. 12 is forwards, 6 is behind, 3 is right, and 9 is left relative to Kent. If Kent is twirling the ball clockwise and lets go at 3, the, the ball will go behind him as the velocity vector exactly at 3 points behind Kent in a clockwise motion. Here are Kents velocity vectors according to my clock analogy. Hope this helps because this is how I learned it!
Imagine this like an analog clock. 12 is forwards, 6 is behind, 3 is right, and 9 is left relative to Kent. If Kent is twirling the ball clockwise and lets go at 3, the, the ball will go behind him as the velocity vector exactly at 3 points behind Kent in a clockwise motion. Here are Kents velocity vectors according to my clock analogy. Hope this helps because this is how I learned it!
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Answer:
a) 12.74 V
b) Two pairs of diode will work only half of the cycle
c) 8.11 V
d) 8.11 mA
Explanation:
The voltage after the transformer is relationated with the transformer relationshinp:
the peak voltage before the bridge rectifier is given by:
The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:
As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.
The averague voltage on a full wave rectifier is given by:
Using Ohm's law: