1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yKpoI14uk [10]
3 years ago
13

All of the following statements are true. Which one can be explained by Kepler's second law?The Sun is not in the precise center

of Saturn's orbit.Earth is slightly closer to the Sun in January than in July.All the planets orbit the Sun in nearly the same plane.Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.Venus orbits the Sun at a faster orbital speed than Earth.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

The answer is: Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.

You might be interested in
Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?
UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

V =\frac{k*q}{r}

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m

r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0
3 years ago
A Molniya orbit is a highly eccentric orbit of a communication satellite so as to provide continuous communications coverage for
likoan [24]

Answer:

Answer: 18.3 km/s

Explanation:

If a satellite in Molniya orbit has an apogee at 48.000 km as measured from the center of Earth, and a velocity of 3.7 km/s. Its velocity in at perigee would be 18.3 km/s.  

6 0
3 years ago
Read 2 more answers
Can someone please help me with these physics problems? I just don’t even know where to start.
KIM [24]

#1

for the block of mass 5 kg normal force is given as

F_n = mg

F_n = 5*9.8 = 49 N

friction force is given as

F_f = \mu F_n

F_f = 0.1*49 = 4.9 N

Net force is given as

F_{net} = ma

F_{net} = 5*2 = 10 N

now we know that

F_{net} = F_{app} - F_f

10 = F_{app} - 4.9

F_{app} = 14.9 N

#2

Normal force is given as

F_n = mg

F_n = 6*9.8

F_n = 58.8 N

now we know that

F_{net} = F_{app} - F_f

F_{net} = 0

as object moves with constant velocity

F_{app} = F_f = 15 N

now for coefficient of friction we can use

F_f = \mu F_n

15 = \mu * 58.8

\mu = 0.255

#3

net force upwards is given as

F = 1.2 * 10^{-4} N

mass is given as

m = 7 * 10^{-5} kg

now as per newton's law we can say

F = ma

1.2 * 10^{-4} = 7 * 10^{-5} * a

a = 1.71 m/s^2

#4

As we know that when block is sliding on rough surface

part a)

net force = applied force - frictional force

F_{net} = F_{app} - F_f

ma = F_{app} - F_f

5*6 = 40 - F_{f}

F_f = 40 - 30 = 10 N

part b)

for coefficient of friction we can use

F_f = \mu F_n

10 = \mu * F_n

here normal force is given as

F_n = mg = 5*9.8 = 49 N

now we have

\mu = \frac{10}{49} = 0.204

#5

if an object is initially at rest and moves 20 m in 5 s

so we can use kinematics to find out the acceleration

d = v_i*t + \frac{1}{2}at^2

20 = 0 + \frac{1}{2}a(5^2)

a = 1.6 m/s^2

now net force is given as

F_{net} = ma

F_{net} = 10*1.6 = 16 N

#6

an object travelling with speed 25 m/s comes to stop in 1.5 s

so here acceleration of object is given as

a = \frac{v_f - v_i}{t}

a = \frac{0 - 25}{1.5} = -16.67 m/s^2

now the force is gievn as

F = ma

F = 5*16.67 = 83.3 N

3 0
4 years ago
A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie
Olin [163]

Answer:

The maximum torque is  \tau_{max} =  1.139 *10^{-7} \ N \cdot m

Explanation:

From the question we are told that

   The length of the wire is  l =  26.0 \ cm  =  0.26 \  m

     The current flowing through the wire is  I  = 5.77mA  =  5.77 *10^{-3} \ A

      The magnetic field is  B = 3.67 \ mT  =  3.67 *10^{-3 } T

         

The maximum torque is mathematically evaluated as

        \tau_{max} =   \mu B  

Where \mu  is the magnetic dipole moment which is mathematically represented as

        \mu  =  \frac{I l^2}{4 \pi n }

Where n is the number of turns which from the question is  1

    substituting values

       \mu  =  \frac{ 5.77 *10^{-3}  *  0.26^2}{4  * 3.142* 1 }

     \mu  =  3.10 4*  10^{-5}  A m^2

Now  

      \tau_{max} =  3.104 *10^{-5} * 3.67 *10^{-3}  

      \tau_{max} =  1.139 *10^{-7} \ N \cdot m  

7 0
3 years ago
Derive the expression for the equivalent resistance of three resistors in[1] paraleli [2] series
sergeinik [125]
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.

When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
8 0
4 years ago
Other questions:
  • Jerri is planning to rebuild the engine of an antique car. She has chosen all the materials she needs including a high quality s
    9·2 answers
  • Witch of the statements is true about scientific theories?
    5·1 answer
  • Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
    11·2 answers
  • What are five electrical devices that don’t need to be plugged into an electrical outlet to operate
    7·1 answer
  • A charge q is at the point x = 5.0 m , y = 0. Write expressions for the unit vectors you would use in Coulomb's law if you were
    13·2 answers
  • When a certain gas under a pressure of 5.00 × 106 Pa at 25.0°C is allowed to expand to 3.00 times its original volume, its final
    8·1 answer
  • The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle invlove and use of which fun
    10·1 answer
  • The drop in potential across a resistor in a circuit is 50 V. What is the current
    9·2 answers
  • An object is 4 cm in front of a converging lens with a focal length of 12 cm
    15·1 answer
  • Astronauts brought back 500 lb of rock samples from the moon. how many kilograms did they bring back? 1 kg = 2.20 lb 227 kg 227
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!