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3 years ago

13

A 120 g block attached to a spring with spring constant 3.0 N/m oscillates horizontally on a frictionless table. Its velocity is

21 cm/s when x0 = -4.1 cm

1 answer:

Marysya12 [62]3 years ago

4 0

Answer:

0.059 m

Explanation:

$0.5k A^2 = 0.5 (k x^{2} + m v^{2})$ where k is the spring constant, A is the amplitude, x is the extension of spring, m is the mass of the spring and v is the velocity in m/s. Making a the subject then

$A = \sqrt{(x^{2} + (\frac {mv^{2}}{k})}$

By substituting the given values then where m is 0.12 Kg, x= 0.0041 m, v is 0.21 m/s and K is 3 N/m then

$A = \sqrt{(0.0041^{2} + (\frac {0.12\times 0.21^{2}}{3})}=0.058694122m\approx 0.059 m$

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Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls f

saw5 [17]

Answer:

The force is of the weight <u>862,4 Newtons.</u>

<u></u>

Explanation:

We have the formula:

w = m * g

Data:

w = weight = ¿?

m = mass = 88 kg

g = gravity = 9,8 m/s

Replacing according formula:

w = 88 kg * 9,8 m/s

Resolving:

w = 862,4 N

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3 years ago

A fleeing student covered a distance of 210 meters in 35 seconds. what is the student's speed in meters/second? what is the stud

snow_lady [41]

Explanation:

Given that,

A student covered a distance of 210 meters in 35 seconds.

We need to find the student's speed in meters/second and also in meters/minute.

Speed, v = distance (d)/time (t)

So,

$v=\dfrac{210\ m}{35\ s}\\\\=6\ m/s$

We know that, 1 minute = 60 seconds

$6\dfrac{m}{s}=6\times \dfrac{m}{(\dfrac{1}{60})\ \text{minutes}}\\\\=360\ \text{meters/minutes}$

Hence, the student's speed is 6 m/s or 360 meters/minute.

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3 years ago

An electric motor is connected to a battery. The current flows through brushes to a commutator ring, which is attached to a elec

Rzqust [24]

Answer:

Commutator is a ring which reverse the direction of current in AC circuit so that the coil connected to it will continuous to move in the same direction.

Explanation:

In motors there exist a coil which is rotated due to torque of magnetic field when current flow through it. Since AC current is used to run the motor so we know that AC current changes its direction after half cycle.

So here commutator plays an important role to reverse the direction of current after every half cycle so that the current goes in same direction always into the coil.

This will produce a constant direction torque on the coil so that it will rotate in same sense always.

So commutator role is to provide same direction current to the coil by reversing its direction after every half cycle

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3 years ago

How can alleles be different?

galina1969 [7]

Answer:

Explanation:

alleles are the different form of certain gene, and for each gene, you have two alleles, one from each parent. For example, you have two alleles for your eye color, let's say a brown allele and a blue allele (genotype Bb) but your physical appearance would be brown eyes (phentotype)

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3 years ago

Find the magnitude of the sum

umka21 [38]

Answer:

Approximately $3.01\; \rm m$ .

Explanation:

Decompose each vector into the sum of two vectors: a horizontal one (parallel to the arrow that points to the right) and a vertical one (parallel the arrow that points upwards.)

Vector $\sf A$ is horizontal and is at an angle of $0^\circ$ with the horizon.

Horizontal component of vector $\sf A$ : to the right, with a length of $5.00\; \rm m \cdot \cos\left(0^\circ \right) = 5.00\; \rm m$ .
Vertical component of vector $\sf A$ : $5.00\; \rm m \cdot \sin\left(0^\circ \right) = 0\; \rm m$ .

Vector $\sf B$ is at an angle of $30^\circ$ below the horizon.

Horizontal component of vector $\sf B$ : to the right, with a length of $\displaystyle 6.00\; \rm m \cdot \cos\left(30^\circ \right) = (6.00\; \rm m) \times \frac{\sqrt{3}}{2}\approx 5.19615\; \rm m$ .
Vertical component of vector $\sf B$ : downwards, with a length of $\displaystyle 6.00\; \rm m \cdot \sin\left(30^\circ \right) = 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m$ .

Calculate the sum of vector $\sf A$ and vector $\sf B$ .

The horizontal component of vector $\sf A$ and vector $\sf B$ are opposite to one another. Therefore, the length of the horizontal component of $\sf (A + B)$ would be the difference between the length of the horizontal components of vector $\sf A\!$ and of vector $\sf B\!$ :

$\displaystyle (6.00\; \rm m) \times \frac{\sqrt{3}}{2} - 5.00\; \rm m \approx 0.196152\; \rm m$ .

The length of the vertical component of vector $\sf A$ is $0\; \rm m$ . Therefore, the length of the vertical component of $\sf (A + B)$ would be equal to the length of the vertical component of vector $\sf B$ , $\displaystyle 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m$ .

Therefore, the length of the horizontal and vertical component of $\sf (A + B)$ are approximately $0.196152\; \rm m$ and $3.00\; \rm m$ , respectively. The length of vector $\sf (A + B)\!$ would be approximately:

$\displaystyle \sqrt{(0.196152\; \rm m)^{2} + (3.00\; \rm m)^{2}} \approx 3.01\; \rm m$ .

5 0

3 years ago