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4 years ago

What are the zeros of the function y= (x+3)(x+2)(x-2) ?

1 answer:

7 0

If you are asking about the x-intercepts, then
x=-3, x=-2, and x=2; this is because these numbers make the equation equal to 0 (or make y=0)
(3,0), (-2,0), and (2,0)

If you are asking about the y-intercept, then you make x=0, which makes the equation (3) times (2) times (-2) which equals -12.
So, the y-intercept is -12.
(0,-12)

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Use the drop-down menus to choose steps in order to correctly solve 4k−6=−2k−16−2 please help just need steps

luda_lava [24]

4k-6=-2k-16-2
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3 years ago

Which representation has a constant of variation of -2.5

Neporo4naja [7]

Answer:

See explanation

Step-by-step explanation:

The constant of variation is found using the slope formula:

$\frac{y_2-y_1}{x_2-x_1}$

The given relation is

X : -2 , -3, -4, -5

Y : -5, -7.5,-10,-12.5

We can use any two ordered pair to find the constant of variation.

Using (-2,-5) and (-3,-7.5), we have

$m=\frac{-7.5--5}{-3--2} =\frac{-2.5}{-1} =2.5$

The constant of variation is 2.5

We need to repeat this for all the options to identify the one with -2.5 as slope.

unfortunately, you did not provide the remaining options.

6 0

3 years ago

Read 2 more answers

The minimum value of f(x) = x3 – 3x2 – 9x + 2 on the interval [–4, 0] is

garri49 [273]

Answer:

-74

Step-by-step explanation:

Graph the function. See attached picture. Between the interval where -4 > x < 0, the graph rises up to a peak and descends back down when x = 0. This means the minimum value will be where x = -4.

Substitute x = -4 into the equation.

f(-4) = (-4)^3 -3(-4)^2 - 9(-4) + 2

f(-4) = -64 -3(16) +36 + 2

f(-4) = -64 - 48 + 36 + 2

f(-4) = -74

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3 years ago

Select the quadratic that has roots x = 8 and x = -5.

Mars2501 [29]

$\text{ The roots are}~ \alpha = 8~ \text{and}~ \beta = -5\\\\\text{Equation for the given roots,}\\\\x^2 -(\alpha +\beta )x +\alpha \beta = 0\\\\\implies x^2 -(8-5)x + 8(-5)=0\\\\\implies x^2 -3x -40=0\\\\\text{Hence, the answer is option B}$

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2 years ago

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