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vfiekz [6]
3 years ago
12

Need help with number 60 I’m really bad at problem solving

Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer:

okay so, i had a problem like this one and hated it, so ill try to help you out here

Step-by-step explanation:

If it is 81 all together it is safe to say the length and width is nine, making one mat six by 3, the little square being 3 by 3,

so the area of one mat would be six times three = 18

and if the width is 3, the length would be 6, unless it is cut in half, which we can assume it is not.

I hope this helps!

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PLEASE HELP!!!!
LekaFEV [45]

Answer:

500

Step-by-step explanation:

It's a box with a square base, so let's say the width and length are x and the height is y.

The surface area of the box without the top is:

A = x² + 4xy

300 = x² + 4xy

The volume of the box is:

V = x²y

Solve for y in the first equation and substitute into the second:

y = (300 − x²) / 4x

V = x² (300 − x²) / 4x

V = x (300 − x²) / 4

V = 75x − ¼ x³

To optimize V, find dV/dx and set to 0:

dV/dx = 75 − ¾ x²

0 = 75 − ¾ x²

x = 10

So the volume of the box is:

V = 75x − ¼ x³

V = 500

The maximum volume is 500 cm³.

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Answer:

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Step-by-step explanation:

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