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3 years ago

Need help with number 60 I’m really bad at problem solving

Mathematics

1 answer:

loris [4]3 years ago

6 0

Answer:

okay so, i had a problem like this one and hated it, so ill try to help you out here

Step-by-step explanation:

If it is 81 all together it is safe to say the length and width is nine, making one mat six by 3, the little square being 3 by 3,

so the area of one mat would be six times three = 18

and if the width is 3, the length would be 6, unless it is cut in half, which we can assume it is not.

I hope this helps!

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If 3 workers can paint a room in 2 hours, then approximately how long does it take 4 workers to paint the same room? Assume the

Olin [163]

It takes 1.5 hours for 4 workers to paint the same room

Solution:

Given that 3 workers can paint a room in 2 hours

To find: Time taken for 4 workers to paint the same room

Assume the time needed to paint the room is inversely proportional to the number of worker

$time $ \propto \frac{1}{\text { number of workers }}\\\\time =k \times \frac{1}{\text { number of workers }}$

Where, "k" is the constant of proportionality

3 workers can paint a room in 2 hours

Substitute number of workers = 3 and time = 2 hours

$time =k \times \frac{1}{\text { number of workers }}\\\\2 = k \times \frac{1}{3}\\\\k = 6$

Therefore,

$\text {time}=6 \times \frac{1}{\text { number of workers }}$

To find time taken for 4 workers to paint the same room, substitute number of workers = 4 in above expression

$time = 6 \times \frac{1}{4} = 1.5$

Thus it takes 1.5 hours for 4 workers to paint the same room

6 0

3 years ago

Read 2 more answers

Sort each description of data into the appropriate category.

Alex787 [66]

Answer:

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

Find the area of the following shape,

lord [1]

$\bold{ANSWER:}$
125.71 cm^2

$\bold{SOLUTION:}$

5 0

2 years ago

Y=2x+4 y=x=6 i need help solving the system of equations

Temka [501]

Answer:

X = 6

Y = 6

Step-by-step explanation:

y = x = 6

we won’t pay attention to the first equation because this equation says that: “y = x” and “x = 6”

so, if x = 6, so will be y

3 0

3 years ago