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boyakko [2]
3 years ago
8

What is the product?

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
4 0

Answer:  The correct option is

(D) 8y^3+6y^2-29y+15.

Step-by-step explanation:  We are given to find the following product :

P=(4y-3)(2y^2+3y-5)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the given product, we must multiply each term of the first expression to each term of the second expression.

The product (i) can be evaluated as follows :

P\\\\=(4y-3)(2y^2+3y-5)\\\\=4y(2y^2+3y-5)-3(2y^2+3y-5)\\\\=8y^3+12y^2-20y-6y^2-9y+15\\\\=8y^3+6y^2-29y+15.

Thus, the required product is 8y^3+6y^2-29y+15.

Option (D) is CORRECT.

topjm [15]3 years ago
3 0

Answer:

8y3 +6y2- 29y +15

Step-by-step explanation:

(4y − 3)(2y2 + 3y − 5)

8y3 + 12y2 -20y -6y2 -9y +15

8y3 +6y2- 29y +15

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A cab charges $1.45 for the flat fee and $0.55 for each mile. Write and solve an inequality to determine how many miles Ariel ca
s344n2d4d5 [400]

9514 1404 393

Answer:

  B. $1.45 + $0.55x ≤ $35; x ≤ 61 miles

Step-by-step explanation:

The mileage charge for x miles will be $0.55x, so the total charge will be $1.45+$0.55x. This must be less than or equal to $35 for Ariel to be able to pay for her travel. The appropriate inequality is ...

  $1.45 +$0.55x ≤ $35 . . . . . matches choice B

__

<em>Comment on selecting an answer</em>

From a "reasonableness" point of view, any answer choice with "≥ $35" can be eliminated immediately. Further, any answer choice with $1.45x can be eliminated, since the mileage charge is not $1.45, it is $0.55. The leaves only the choice shown above.

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4 years ago
What are two more ways to arrange the cars into even rows?
kotykmax [81]

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make both sides even by putting the same amount of cars on either side

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
On 31 August 2018,Musk Traders purchased a machine on credit for a cost price of R402 500(including VAt at 15%). Machinery is de
mariarad [96]

Answer:

Depreciation should be on a value net of VAT.

Cost + (Cost * VAT) = 402,500

Cost + Cost * 15% = 402,500

1.15 * Cost = 402,500

Cost = $350,000

Depreciation is straight line for 6 years so per year is = 350,000/6 = $58,333

2019

In 2019 the June year end from date of purchase will be 10 months.

Depreciation in 2019

= Yearly depreciation * 10/12 months

= 58,333 * 10/12

= $48,611

Accumulated Depreciation 2019

= $48,611

2020

2020 will be a complete year so depreciation

= $58,333

Accumulated Depreciation 2020

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4 0
3 years ago
BRAINLIESTTTTT ASAP!!!
Alina [70]
X^2 - 2x - 3 = 0
(x^2 - 2x +  ) - 3 -  = 0
(x^2 - 2x + 1) - 3 - 1 = 0
(x - 1)^2 - 4 = 0
(x - 1)^2 = 4
3 0
4 years ago
What is 8n=3m 1;n=-2,2,4
algol [13]
8n = 3m + 1
~~~~~~~~~~~~~~~~~~~
8(-2) = 3m + 1
-16 = 3m + 1
-1 -1
-17 = 3m
--- ---
3 3
-17/3 = m
~~~~~~~~~~~~~~~~~~~
8(2) = 3m + 1
16 = 3m + 1
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15 = 3m
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3 3
5 = m
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8(4) = 3m + 1
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31 = 3m
--- ---
3 3
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3 years ago
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