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3 years ago

What is the product?

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

4 0

Answer: The correct option is

(D) $8y^3+6y^2-29y+15.$

Step-by-step explanation: We are given to find the following product :

$P=(4y-3)(2y^2+3y-5)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To find the given product, we must multiply each term of the first expression to each term of the second expression.

The product (i) can be evaluated as follows :

$P\\\\=(4y-3)(2y^2+3y-5)\\\\=4y(2y^2+3y-5)-3(2y^2+3y-5)\\\\=8y^3+12y^2-20y-6y^2-9y+15\\\\=8y^3+6y^2-29y+15.$

Thus, the required product is $8y^3+6y^2-29y+15.$

Option (D) is CORRECT.

topjm [15]3 years ago

3 0

Answer:

8y3 +6y2- 29y +15

Step-by-step explanation:

(4y − 3)(2y2 + 3y − 5)

8y3 + 12y2 -20y -6y2 -9y +15

8y3 +6y2- 29y +15

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