Can someone help please!!
1 answer:
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Hi there!
Combining th' like terms of the expressions.
(7y² - 3y) + (8y² - 8y)
7y² - 3y + 8y² - 8y
(7y² + 8y²) + (-3y - 8y)
15y² - 11y
Hence,
Option [ 1. ] - 15y² - 11y is Correct
~ Hope it helps!
Combining th' like terms of the expressions.
(7y² - 3y) + (8y² - 8y)
7y² - 3y + 8y² - 8y
(7y² + 8y²) + (-3y - 8y)
15y² - 11y
Hence,
Option [ 1. ] - 15y² - 11y is Correct
~ Hope it helps!
Answer:
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one
<em>For the graph below, what should the domain be so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200 </em>
My answer:
Given the above information, we have:
To make the function is at least 200, it means that:
≥ 200
<=> ≥ 0
<=> x(-2x+30) ≥ 0
This is the product of two numbers hence would be positive only if either both are positive or both are negative
- Case I: Both positive
x ≥ 0 and (-2x+30) ≥ 0
<=> 0 ≤ x ≤ 15
- Case II: Both negative
Then we get
This is inconsistent as a value cannot be less than 0 and greater than 15
=> our correct answer is
Hope it will find you well.
Given the vertex, (2, -4) as the minimum point, and that it is an upward-facing parabola that passes point (1, -2):
We could substitute these values into the vertex form of the quadratic function,
f(x) = a(x - h)^2 + k
where:
(h,k) is the vertex
The axis of symmetry is the vertical line x = 2
The value of “a” determines whether the graph opens up or down, and makes the parent function wider or narrower.
The value of “h” determines how far left or right the parent function is translated.
The value of “k” determines how far up or down the parent function is translated.
Now that we’ve established these definitions, we can substitute the given values into the vertex form:
f(x) = a(x - 2)^2 - 4
In order to determine the value of “a”, we must substitute the values of the other given point, (1, -2) into the equation:
f(x) = a(x - 2)^2 - 4
-2 = a(1 - 2)^2 - 4
-2 = a(-1)^2 - 4
-2 = a - 4
Add 4 to both sides to solve for “a”
-2 + 4 = a - 4 + 4
2 = a
Now that we have the value of a = 2, we can establish our quadratic function in vertex form:
f(x) = 2(x - 2)^2 - 4
I’m also including a screenshot of the graph of the function we came up with.
Please mark my answers as the Brainliest if you find my explanations helpful :)
We could substitute these values into the vertex form of the quadratic function,
f(x) = a(x - h)^2 + k
where:
(h,k) is the vertex
The axis of symmetry is the vertical line x = 2
The value of “a” determines whether the graph opens up or down, and makes the parent function wider or narrower.
The value of “h” determines how far left or right the parent function is translated.
The value of “k” determines how far up or down the parent function is translated.
Now that we’ve established these definitions, we can substitute the given values into the vertex form:
f(x) = a(x - 2)^2 - 4
In order to determine the value of “a”, we must substitute the values of the other given point, (1, -2) into the equation:
f(x) = a(x - 2)^2 - 4
-2 = a(1 - 2)^2 - 4
-2 = a(-1)^2 - 4
-2 = a - 4
Add 4 to both sides to solve for “a”
-2 + 4 = a - 4 + 4
2 = a
Now that we have the value of a = 2, we can establish our quadratic function in vertex form:
f(x) = 2(x - 2)^2 - 4
I’m also including a screenshot of the graph of the function we came up with.
Please mark my answers as the Brainliest if you find my explanations helpful :)