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Helen [10]
4 years ago
15

Which is equivalent in the answers??

Mathematics
1 answer:
kifflom [539]4 years ago
5 0

Answer:

i need this tooooooooooooooooooooo

Step-by-step explanation:

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Answer The Question On The Picture
taurus [48]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Graph the function. Then State the domain and range. Also increasing and decreasing​
masha68 [24]

Answer:

See below, I will let graphing part to yourself.

Step-by-step explanation:

First function: domain: [-9,\infty), range: (-\infty, -2], decreasing

Second function: domain: (-\infty, \infty), range: (-\infty, \infty), increasing

Third function: domain: [3, \infty), range: [-5,\infty), increasing

4 0
3 years ago
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Some of the steps for completing the square to solve
Korvikt [17]

Answer:

option D and E just did it hope i help

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve for x using desmos or the quadratic formula 2x^2 - 5x - 12 = 0
ivanzaharov [21]

Answer:

x = 4 or x = (-3)/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 - 5 x - 12 = 0

x = (5 ± sqrt((-5)^2 - 4×2 (-12)))/(2×2) = (5 ± sqrt(25 + 96))/4 = (5 ± sqrt(121))/4:

x = (5 + sqrt(121))/4 or x = (5 - sqrt(121))/4

sqrt(121) = sqrt(11^2) = 11:

x = (5 + 11)/4 or x = (5 - 11)/4

(5 + 11)/4 = 16/4 = 4:

x = 4 or x = (5 - 11)/4

(5 - 11)/4 = -6/4 = -3/2:

Answer:  x = 4 or x = (-3)/2

5 0
3 years ago
Read 2 more answers
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
3 years ago
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