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3 years ago

HELP PLEASE ASAP !!! ON THE LAST QUESTION NEED IT AS SOON AS POSSIBLE !! 10 points

1 answer:

6 0

First blank: not random Because he sent it to the top 5 students. Not random students throughout the grade.

second blank: I would guess not valid because it was not a random sample.

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The two triangles below are similar. What is the ratio of the corresponding side lengths? 4:9 4:2 26:26 4.5:2

MrRa [10]

Answer:

4 : 2

Step-by-step explanation:

We are given ΔABC ≅ ΔA'B'C'.

When two triangles are congruent, their corresponding sides and angles are congruent.

Since, the sides of the triangles are in relation,

AB = 2 × A'B' and side BC = 2 × B'C' i.e. 4 = 2 × 2 and 9 = 2 × 4.5.

Therefore, the ratio of the corresponding sides are given by 4 : 2 and 9 : 4.5 i.e. 2 : 1.

Since, the ratio of the corresponding sides comes out to be 2 : 1 = 4 : 2.

Hence, the ratio of the corresponding sides is 4 : 2.

8 0

3 years ago

Read 2 more answers

( PLEASE HELP BONUS POINTS ) The bases of a trapezoid or 24 ft and 16 feet. the height of the trapezoid is 12 feet. What is the

mote1985 [20]

Answer: 240 feet squared

Step-by-step explanation: A=(b1+b2)h is formula used for trapezoids.

Plug the appropriate numbers in and solve.

7 0

3 years ago

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$