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Allisa [31]
3 years ago
5

Please help me with this I need the right answer

Mathematics
2 answers:
Grace [21]3 years ago
8 0

Answer:

B is the correct answer.

Step-by-step explanation:

graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).

Alex3 years ago
3 0

Answer:

B

Step-by-step explanation:

B is the correct answer

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Suppose you choose a marble from a bag containing 6 red marbles , 2 white marbles and 5 blue marbles you return the first marble
algol [13]

Answer:

30/169

Step-by-step explanation:

We need to know how many marbles in the bag

6 red marbles + 2 white marbles + 5 blue marbles = 13 marbles

P (red) = red / total = 6/13

We then put the marble bad so there are still 13 marbles in the bag

P(blue) = blue /total = 5/13

P (red then blue ) = P(red) *P(blue)

                             = 6/13 * 5/13 = 30/169

8 0
3 years ago
The football program has 14 footballs that weigh 2.57 pounds each. How much do the footballs weigh all together?
Darina [25.2K]

Answer:

35.98 pounds

Step-by-step explanation:

6 0
3 years ago
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Lydia was out at a restaurant for dinner when the bill came. Her dinner came to $30. After adding in a tip, before tax, she paid
Aloiza [94]

Answer:

15%

Step-by-step explanation:

34.50-30=4.50

10% of 30= 3

5%of 30 = 1.50

3+1.50=4.50

so 4.50 = 15%

7 0
3 years ago
Read 2 more answers
1. Solve the following equation: (1 Point) 3 - 4 = -3​
Brut [27]

Answer:

Step-by-step explanation:

bheggrybcgdbceufbuebruebvrbvyuerbyvrbeyrbvyeby7beuvbhyuerbrbvuyerbvyuhdeijbcgyfdhebvuchgfeuvcbjhdev hvdbetycun

6 0
3 years ago
A bag contains marbles: 5 red, 2 blue, and 1 green. You pick a marble and then another one without replacement. What is the prob
max2010maxim [7]

hi

1st draw: green

2/12. (2 green out of 12 marbles), reduces to 1/6

2nd draw: blue

4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)

Probability of theses BOTH happening: multiply these individual probabilities.

Conditional probability:

P(a and b) = P(a)P(b|a)

Prob(event 1) × Prob(event 2 given event 1).

1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.

5 0
2 years ago
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