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3 years ago

Solve F(x) for the given domain

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

Answer:

The correct answer is A) 2

Step-by-step explanation:

In order to find this, input 1 into the equation for each value of x that you see.

f(x) = x^2 + 3x - 2

f(1) = 1^2 + 3(1) - 2

f(1) = 1 + 3 - 2

f(1) = 2

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caitlyn has $210 in her savings account and she has to pay her parents $5 each month.Santos has $90 dollars and he saves $5 doll

nevsk [136]

Answer:

After about 12 months both Caitlyn and Santos will have the same balance of 150 dollars in their bank account.

Step-by-step explanation:

Caitlyn's saving: -5x+210

Santos' saving: 5x+90

To know when the total amount in their bank account is the same you would need to make these linear equations equal to one another.

-5x+210 = 5x+90

(Add 5x on both sides)

210=10x+90

(Subtract 90 from both sides)

120=10x

(Simplify)

x=12

After about 12 months their total savings should be the same. To check what their balance will be plug the x value of 12 into both of these equations. This should give 150 as your answer for both equations.

5 0

3 years ago

Write the expanded form of 9,003,840,165

Tanya [424]

9,000,000,000 + 3,000,000 +800,000 +40,000 + 100 + 60 +5

~ Here you go (/>ω<)/

6 0

3 years ago

Read 2 more answers

Please tell me the steps to this problem. i will give brainliest

gayaneshka [121]

Option C: -3 is the average rate of change between $x=-1$ and $x=1$

Explanation:

The formula to determine the average rate of change is given by

Average rate of change = $\frac{y_2-y_1}{x_2-x_1}$

We need to find the average rate of change between $x=-1$ and $x=1$

Thus, from the table, we have,

$x_1=-1$ , $y_1=5$

$x_2=1$ , $y_2=-1$

Thus, substituting these values in the formula, we get,

Average rate of change = $\frac{-1-5}{1+1}$

$=\frac{-6}{2}$

$=-3$

Thus, the average rate of change between $x=-1$ and $x=1$ is -3.

Hence, Option C is the correct answer.

6 0

3 years ago

Please help with this

solong [7]

Could you retake the picture it’s hard to read

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3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

4 years ago