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denis23 [38]
3 years ago
13

The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equat

ion solved for V?
Mathematics
2 answers:
Cloud [144]3 years ago
5 0
Another equation to get V is mass/density. 
A way to get density is mass/volume
A way to get mass is density times mass. 
I know you didn't ask for the other equations, but I listed them to show how density, volume, and mass are related. To answer your question, to get volume you divide mass by density.
tensa zangetsu [6.8K]3 years ago
4 0
D = m / V

Multiply both sides by V

dV = m
Divide both sides by d:-

V = m /V   Answer
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3 years ago
4 ftA wire isneeded tosupport averticalpole 4 feettall. Thecable willbeanchoredto a stake3 feet fromthe baseof thepole. How3 ftA
Oxana [17]

SOLUTION

From the image in the question, we can see that it is a right triangle problem.

And we can use the Pythagoras theorem to solve for the length of cable wire needed.

Pythagoras theorem states that:

\begin{gathered} \text{hypotenuse}^2=opposite^2+adjacent^2 \\ x^2=4^2+3^2 \end{gathered}\begin{gathered} x^2=16+9 \\ x^2=25 \\ \text{Take the square roots of both sides:} \\ \sqrt[]{x^2}=\sqrt[]{25} \\ x=5ft \end{gathered}

Final Answer:

A cable of length 5 feet is needed.

5 0
1 year ago
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Svet_ta [14]

Answer:

α = 27.9794744° ≈ 28.0 m (nearest tenth)

Step-by-step explanation:

Step 1:

Opposite (O) = 42.5 (the side opposite to the reference angle, α)

Adjacent (A) = 80

Hypotenuse (H) = the longest side opposite to the right angle

2. We are given the adjacent (A) and opposite (O) lengths, we would use TOA. Which is:

Tan α = Opp/Adj

Plug in the values

Tan α = 42.5/80

3. Make α stand alone

α = tan^{-1}(\frac{42.5}{80})

4. α = 27.9794744° ≈ 28.0 m (nearest tenth)

8 0
2 years ago
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