Answer: 100.335283 m2
Step-by-step explanation: L x W x H
I think the answer would be $58
SOLUTION
From the image in the question, we can see that it is a right triangle problem.
And we can use the Pythagoras theorem to solve for the length of cable wire needed.
Pythagoras theorem states that:

![\begin{gathered} x^2=16+9 \\ x^2=25 \\ \text{Take the square roots of both sides:} \\ \sqrt[]{x^2}=\sqrt[]{25} \\ x=5ft \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%3D16%2B9%20%5C%5C%20x%5E2%3D25%20%5C%5C%20%5Ctext%7BTake%20the%20square%20roots%20of%20both%20sides%3A%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B25%7D%20%5C%5C%20x%3D5ft%20%5Cend%7Bgathered%7D)
Final Answer:
A cable of length 5 feet is needed.
Answer:
α = 27.9794744° ≈ 28.0 m (nearest tenth)
Step-by-step explanation:
Step 1:
Opposite (O) = 42.5 (the side opposite to the reference angle, α)
Adjacent (A) = 80
Hypotenuse (H) = the longest side opposite to the right angle
2. We are given the adjacent (A) and opposite (O) lengths, we would use TOA. Which is:
Tan α = Opp/Adj
Plug in the values
Tan α = 42.5/80
3. Make α stand alone
α = 
4. α = 27.9794744° ≈ 28.0 m (nearest tenth)