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Vadim26 [7]
3 years ago
7

2/5x+10=30 a- x=100 b-x=12 c-x=50 d-x=16

Mathematics
2 answers:
garri49 [273]3 years ago
6 0

Answer:

C: x=50

Step-by-step explanation:

Sever21 [200]3 years ago
3 0

Answer:

x=50

Step-by-step explanation:

x in (-oo:+oo)

(2/5)*x+10 = 30 // - 30

(2/5)*x-30+10 = 0

2/5*x-20 = 0 // + 20

2/5*x = 20 // : 2/5

x = 20/2/5

x = 50

x = 50

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Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ?
skelet666 [1.2K]

Angles formed by the segment \overline{XZ} in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

  • The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment \overline{XZ} is perpendicular to segment \overline{WY}

∠WZX and ∠XZY are right angles by definition of \overline{XZ}  perpendicular to \overline{WY}

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}

\displaystyle \mathbf{ \frac{XZ}{ZY}}  = \frac{12}{9}  = \frac{4}{3}

Therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9}, which gives, \displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

  • \displaystyle \frac{16}{12} = \frac{12}{9} which is; <u>16 over 12 equals 12 over 9</u>

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

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Which of the following is the surface area of the right cylinder below?
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