Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
I don't know this sorry is there any other way I could help you
Answer:
decimal form: 0.05
Step-by-step explanation:
To find decimals divide them, so 2 divided by 40 is 0.05.
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Answer:
∠ I = 39°, ∠ J = 51°, ∠ K = 90°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the3 angles and equate to 180
3x + 21 + 5x + 21 + 90 = 180, that is
8x + 132 = 180 ( subtract 132 from both sides )
8x = 48 ( divide both sides by 8 )
x = 6
Then
∠ I = 3x + 21 = 3(6) + 21 = 18 + 21 = 39°
∠ J = 5x + 21 = 5(6) + 21 = 30 + 21 = 51°
∠ K = 90°
Answer:
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Diameter of a circle is 8 cm. Then find out the area and perimeter of the circle.
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Area of circle is 50.29(≈)cm² and perimeter of circle is 25.14(≈)cm.
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•Given :-
Diameter of the circle = 8 cm.
•To find :-
Area and perimeter of the circle.
• Solution :-
Let the radius of the circle be r cm.
Diameter = 8 cm.
We know,
★
So, Radius (r) = 8/2= 4 cm.
We know,
★
Area of circle= πr²
→Area of circle=
→Area of circle=
→Area of circle= 50.29(≈)cm²
____________________________
We know,
★
Perimeter of circle= 2πr
→ Perimeter of circle=
→Perimeter of circle=25.14(≈)cm