Answer:
The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Z-table as such z has a p-value of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?
A sample of n is needed, and n is found when M = 4. So






The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
Average speed the others are categorical.
Answer:
9/10
30%
Step-by-step explanation:
Only in trial number 4, there is just one correct answer. In all other 9 trials at least 2 answers were correct. So the probability is 9 out of 10 trials give a winning outcome, in short, 9/10.
Giving birth to three males first, is true in 3 out of 10 trials. You can count the total numbers of Y's in the last column.
So 3/10 which is 0.3 which is the same as 30%.
Let the number that wll be added be x, then
-7/9 + x = 5
x = 5 + 7/9 = 5 7/9 or 52/9
The answer is B on edgeunity