Answer:
a). Nadia made a total of $825 last week in commission sales
b). The total amount Nadia in commission in 2011=$42,900
Step-by-step explanation: Total amount (2011)=Average weekly commission × number of weeks in 2011 where; Average weekly commission=$825 number of weeks in 2011=52 replacing; Total amount (2011)=(825×52)=42,900
. The total amount Nadia in commission in 2011=$42,900.
C and D!
Please let me know if you want explanation.
Answer:
29. D
30. A
31. C
32. B
33. A
Step-by-step explanation:
Sides of first rectangle are 12 inches and 6 inches
and sides of second rectangle are 10 inches and 5 inches
So to find the ration of sides we can do
Ratio of bases = 12/10 = 6/5
Ratio of altitudes = 6/5
Area of first rectangle = base * altitude = 12 *6 = 72 square inches
Answer:

Step-by-step explanation:
+6x-5=0
we divide the coefficient of the X by half :
in this case: 6/2 = 3 , then we do the following
The result obtained is raised to square power: 3^2=9
we sum and subtract by 9 to maintain the balance of the equation:
+6x+9-9-5=0
we have:
-9-5=0
= 14
lets apply square root on both sides of the equation:

we know:

so we have:
abs(x+3)=
from where two solutions are obtained

finally we have:
