answer : option C

Lets find the number of zeros by factoring

Group first two terms and last two terms

Factor out GCF from each group


Now we set each factor =0 and solve for x
0 = (x^2-8) and (x + 1)=0
and x = -1
and x= -1
So we have three real zeros
The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.
Answer: I think so
Step by step:
Answer:
3,4,5,6,7,8,9,10
Step-by-step explanation:
is this what u meant ?
Answer:
18a +9
Step-by-step explanation:
9 (2a + 1)
Distribute the 9
9*2a + 9*1
18a +9