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ZanzabumX [31]
3 years ago
10

P= x/3 and x = 1/2 y. Write p in terms of y

Mathematics
1 answer:
Finger [1]3 years ago
8 0

Answer:

p = 1/2y - 3

Step-by-step explanation:

p=x/3 and x=1/2y [replace the "x" to solve]

p = (1/2y)/3

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According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

This is a left tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

µ = population mean = 17

s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0
3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
Door
maksim [4K]

Answer:

77

Step-by-step explanation:

that is the answer i got i did a quiz with the same question not too long and i got a 100 and i putt 77 aas my answer!!!!!!!!1

6 0
3 years ago
Each month your cell phone company charges you $ 50 for your plan plus 3 cents for each text you send. You have $ 140 budgeted f
pshichka [43]

Answer:

3000 text messages can be sent without breaking the budget.

Step-by-step explanation:

Since each month your cell phone company charges $ 50 for your plan plus 3 cents for each text you send, and you have $ 140 budgeted for cell phone expenses for the month, to make a determination about the number of texts you can send each month the following calculation must be performed:

(140 - 50) / 0.03 = X

90 / 0.03 = X

3000 = X

Therefore, 3000 text messages can be sent without breaking the budget.

7 0
3 years ago
Plz plz help
viktelen [127]
X^2 - 10 = 3x
X^2 - 3x - 10 = 0
(x - 5) (x + 2) = 0
x = 5 and x = -2
Answer: x = -2
6 0
3 years ago
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