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pshichka [43]
4 years ago
13

State the intervals for which the given quadratic is positive and when it is negative.

Mathematics
1 answer:
goblinko [34]4 years ago
3 0

Answer:

  • Positive at (-9, 2)
  • Negative at ( -oo, -9) or (2, + oo)

Step-by-step explanation:

<u>Given function</u>

  • y= -2x^2 - 14x + 36

<u>Getting zero's</u>

  • -2x^2 - 14x + 36 = 0
  • x^2 + 7x - 18 = 0
  • x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
  • x = - 9 and x = 2

<u>As the x^2 has negative coefficient, the function is positive between -9 and 2</u>

  • - 9 < x < 2 or
  • (-9, 2)

<u>And it is negative at:</u>

  • x < -9 and
  • x > 2
  • or
  • ( -oo, -9) or (2, + oo)

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Answer:

No solution.

Step-by-step explanation:

Step 1: Write inequality

3(x - 2) + 1 ≥ x + 2(x + 2)

Step 2: Solve for <em>x</em>

  1. Distribute: 3x - 6 + 1 ≥ x + 2x + 4
  2. Combine like terms: 3x - 5 ≥ 3x + 4
  3. Add 5 to both sides: 3x ≥ 3x + 9
  4. Subtract 3x on both sides: 0 ≥ 9

Here we see that the statement is false. Therefore, you cannot solve for the inequality.

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In a neutral atom that has an atomic mass of 22 and atomic number of 12, how many neutrons does this element have?
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Given :

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To Find :-

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Solution :-

<u>As </u><u>we</u><u> know</u><u> that</u><u>,</u>

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irakobra [83]
X is the smaller number. 3x + 15 is the larger number. So x + 3x + 15 = 63. 4x + 15 = 63.
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