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pshichka [43]
3 years ago
13

State the intervals for which the given quadratic is positive and when it is negative.

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

  • Positive at (-9, 2)
  • Negative at ( -oo, -9) or (2, + oo)

Step-by-step explanation:

<u>Given function</u>

  • y= -2x^2 - 14x + 36

<u>Getting zero's</u>

  • -2x^2 - 14x + 36 = 0
  • x^2 + 7x - 18 = 0
  • x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
  • x = - 9 and x = 2

<u>As the x^2 has negative coefficient, the function is positive between -9 and 2</u>

  • - 9 < x < 2 or
  • (-9, 2)

<u>And it is negative at:</u>

  • x < -9 and
  • x > 2
  • or
  • ( -oo, -9) or (2, + oo)

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Jennifer will be driving to Las Vegas this weekend. From her home to the hotel she will be staying at is 1,345 miles away. If Je
Zarrin [17]

Answer:

It will take 19.2142857 hours

Step-by-step explanation:

1,345/70

Round to what you're required.

8 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
The sides of a triangle are consecutive integers.if its perimeter is 126cm,find the lenghts of the sides.
Neko [114]
X + (x + 1) + (x + 2) = 126
3x = 123
x = 41
So the sides are 41, 42 and 43


3 0
4 years ago
Eight less than the product of 2 and a number x ?
mars1129 [50]
Eight less than the product of 2 and a number x is: 2x-8
4 0
3 years ago
Read 2 more answers
Caitlin has 4 3/4 pounds of clay . She uses 1 1/10 pounds to make a cup ,and another 2 pounds to make a jar , how many pounds ar
Brut [27]
There are 33/20 or 1.65 pounds left.

Given:
4 3/4 pounds of clay
1 1/10 pounds of clay for a cup
2   pounds of clay for a jar

Convert the mixed fraction into fractions.
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1 1/10 = (1*10+1)/10 = 11/10
2 = 2/1

19/4 - 11/10 = (19/4 *5/5) - (11/10 * 2/2) = 95/20 - 22/20
= (95-22)/20 = 73/20 or 3.65 pounds after making a cup  

73/20 - 2/1 = 73/20 - (2/1 * 20/20) = 73/20 - 40/20 = 73 - 40 / 20 = 33/20  OR 1.65 pounds left after making a jar.


We can also convert the fractions into decimal numbers.
19/4   = 4.75
11/10 = 1.10
2/1     = 2.00

4.75 - 1.1 - 2 = 1.65 pounds left.


5 0
3 years ago
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