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Citrus2011 [14]
3 years ago
9

WILL GIVE BRAINLIEST What are the like terms in the algebraic expression? Negative a squared b + 6 a b minus 8 + 5 a squared b m

inus 6 a minus b Negative a squared b and negative 6 a Negative a squared b and 5 a squared b 6 a b and 5 a squared b 6 a b and negative 6 a
Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

Minchanka [31]3 years ago
4 0

Answer: B

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

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<u>Given equation:</u>

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<u>We know that a box survives 1/5 a day.</u>

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In general, the point
Zanzabum

Answer:

we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

Step-by-step explanation:

Given the function

f(x) = abˣ

Let us substitute all the points one by one

FOR (b, 0)

y = abˣ

putting x = b, y = 0

0 = abᵇ

FOR (a, b)

y = abˣ

putting x = a, y = b

b = abᵃ

FOR (0, 0)

y = abˣ

putting x = 0, y = 0

0 = ab⁰

0 = a         ∵b⁰ = 1

FOR (0, a)

y = abˣ

putting x = 0, y = a

a = ab⁰

a = a         ∵b⁰ = 1

TRUE

Thus, we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

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6 0
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