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Citrus2011 [14]
3 years ago
9

WILL GIVE BRAINLIEST What are the like terms in the algebraic expression? Negative a squared b + 6 a b minus 8 + 5 a squared b m

inus 6 a minus b Negative a squared b and negative 6 a Negative a squared b and 5 a squared b 6 a b and 5 a squared b 6 a b and negative 6 a
Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

Minchanka [31]3 years ago
4 0

Answer: B

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

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WILL MAKE BRAINLIEST!!! A Ferris wheel has a diameter of 220 feet and the center of the wheel is 125 feet above the ground. The
daser333 [38]
Since the radius of a circle is half its diameter, the radius of our Ferris wheel is r= \frac{220}{2} =110ft

Next, we are going to convert from revolutions per minute to degrees per second.
We know that t<span>he wheel makes a complete turn every 2 minutes, so it makes a complete turn in 120 seconds. Since there are 360° in a complete turn, we can set up our conversion factor:
</span>\frac{1*360}{120}=3 degrees per second 
<span>
Now, lets find the height:
</span>We know that <span>the passenger is at the lowest point on the wheel when t=0; since the wheel is 125 feet above the ground, at t=0 h=125. To find t at the top, we are going to take advantage of the fact that the wheel will turn 180° from the lowest point to the top and that it turns 3° every second:
</span>t= \frac{180}{3}
t=60
Notice that the height at the top is the diameter of the wheel plus the height above the ground, so h=220+125=345.

To model the situation we are going to use the cosine function, but notice that cos (\alpha) is 1 when \alpha =0 and -1 wen \alpha =180. Since we want the opposite, we are going to use negative cosine.
Notice that we want \alpha =180 when t=60, so we are going to use -cos(3t). Next, we are going to multiply our cosine by the radius of our wheel: -110cos(3t), and last but not least we are going to add the sum of the radius of the wheel plus the height above the ground:
h=110+125-110cos(3t)
h=225-110cos(3t)

Now that we have our height function lets check if everything is working:
<span>the passenger is at the lowest point at t=0; we also know that the lowest point is 125 feet above the ground, so lets evaluate our function at t=0:
</span>h=225-110cos(3t)
h=225-110cos(3*0)
h=125 feet 
So far so good. 
We also know that at t=60, our passenger is 345 feet above the ground, so lets evaluate our function at t=60 and check if coincides:
h=225-110cos(3t)
h=225-110cos(3*60)
h=225-110cos(180)
h=345feet 

We can conclude that cosine function that express the height h (in feet) of a passenger on the wheel as a function of time t (in minutes) ) is: h=225-110cos(3t)
8 0
3 years ago
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