Answer:
The path of second ship is represented as coordinate plane as line y = - 13 x + 44 . Answer
Step-by-step explanation:
Given as :
The path of one ship represented as line
y = - 13 x + 4
The standard equation of line is
y = m x + c
where m is the slope of line and c is the y-intercept
Now, comparing the line equations
The slope of line , y = - 13 x + 4 is m = - 13
Now, second ship passes through point (3 ,5) and parallel to first ship
For Parallel line condition
The slope of both lines are equal
Let The slope of second ship = M
So, M = m = - 13
Now, Equation of line with slope - 13 and passing through point (3 , 5)
y -
= M × ( x -
)
Or, y - 5 = - 13 × (x - 3)
Or, y - 5 = -13 x + 39
Or, y = - 13 x + 39+ 5
i.e y = - 13 x + 44
So, The path of second ship is represented as coordinate plane as line y = - 13 x + 44
Hence, The path of second ship is represented as coordinate plane as line y = - 13 x + 44 . Answer