Answer:
import numpy as np#importing numpy module with an alias np.
def c(bitstring_array):# defining function c.
num_integer=bitstring_array.dot(2**np.arange(bitstring_array.size)[::-1])#bitstring conversion.
return num_integer#returning integer array.
print("Enter bits")
Bit_l=input().split(" ")#enter space separated bitstring.
for i in range(len(Bit_l)):#iterating over the bitstring.
Bit_l[i]=int(Bit_l[i])
bitstring_array=np.array(Bit_l)
print(c(bitstring_array))#function call.
Output:
Enter bits
1 1 1 0 0 1
57
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
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Light Amplification by Stimulated Emission of Radiation
did you just put random a*s word together and expect us to know the ¨answer¨
