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BARSIC [14]
3 years ago
5

If the speakers are not working on a laptop, what could be the problem besides the speakers?

Computers and Technology
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer:

Sound card

Explanation:

In computer or laptop music or sound files are stored in digital form. Sound card is the the device that is used to convert the digital form of music into analog to produce the signal that is compatible with speaker or microphone.

If the speakers are not working on the laptop, means there is no sound produced on speakers. It means that sound card is not working properly.

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3 years ago
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A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
ENG103 DISCUSSION BOARD 6
amm1812
The proper citation for your course of study -computer related- is APA (American Psychological Association)  format. This citation format allows us to state the publication date, title , and authors in an organized and short fashion. All scholarly reports that are technology or psychology based, should be cited in APA format. 

<span>I know this because it is the format I use for all of my college courses which are all Computer/Technology related. </span>
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Function signature I think
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Whers the main characteristic of a Peer-to-peer (P2P) network?
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The answer to this would be B

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