Answer:
// here is code in the C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable to store the input
int birth_month,birth_year;
cout<<"enter birth month:";
// read the birth month
cin>>birth_month;
cout<<"enter birth year:";
// read the birth year
cin>>birth_year;
// print the output
cout<<birth_month<<"/"<<birth_year<<endl;
return 0;
}
Explanation:
Declare two variables to store the birth month and birth year.Read the inputs from the user and assign it the variables.Print the birth month and year separated by a slash "/".
Output:
enter birth month:1
enter birth year:2000
1/2000
def is_list_even(my_list):
for i in my_list:
if(i%2 != 0):
return False
return True
def is_list_odd(my_list):
for i in my_list:
if(i%2 == 0):
return False
return True
def main():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
if(is_list_even(lst)):
print('all even')
elif(is_list_odd(lst)):
print('all odd')
else:
print('not even or odd')
if __name__ == '__main__':
main()
Answer:
The result of the following code will be 9
Explanation:
There are several operators used in Python to do mathematical calculations.
** operator is used for exponents.
i.e.
a ** b mathematically means a^b
Here in the given code
3 is assigned to numA and 2 is assigned to numB
Result will be equal to 3^2
Hence,
The result of the following code will be 9
Answer:
Continuous Integration
Explanation:
In continuous integration process, A program or piece of code is edited, tested and validated by team of software developers or contributors to complete and deploy the single project. This practice will improve the quality and reliability of the code.
Improvement, delivery and deployment are the three different phases, to complete the process of continuous integration.The individuals who contribute in a code or program in terms of improvement, delivery and deployment make a team that leads to continuous integration.
So, Agile team Continuously adapt Continuous Integration to new circumstances and enhance the methods of value delivery.
Segundo o padrão da National Institute of Standards and Technology a alternativa correta é a letra E) 400 músicas. Segundo o padrão disposto acima, dois Giga Bytes equivalem à dois mil Mega Bytes, assim, se cada música tem exatos 5MB, podemos chegar ao total de músicas que podem ser gravadas em um PenDrive de 2GB livres do seguinte modo :
A evolução da microeletrônica possibilitou uma capacidade de armazenamento cada vez maior a cada ano. O desenvolvimento de novas tecnologias na área permite também que os produtores possam produzir músicas, fotos e vídeos com cada vez mais qualidade (consequentemente mais pesada).
